3 years ago

Pls help me on this equation

Mathematics

1 answer:

MArishka [77]3 years ago

6 0

I think the answer is A

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What is the slope of the line that passes through the points (-10, -8)(−10,−8) and (-8, -16) ?(−8,−16)? Write your answer in sim

photoshop1234 [79]

The slope of the line that passes through points ( -10, -8 ) and ( -8, -16 ) is -4.

<u>Explanation:</u>

Points given = ( -10, -8) and ( -8, -16)

Slope = ?

( -10, -8 ) : x1 = -10 and y1 = -8

( -8, -16 ) : x2 = -8 and y2 = -16

We know,

slope = y2 - y1 / x2 - x1

Slope = -16 - ( -8) / -8 - (-10)

slope = -16 + 8 / -8 + 10

slope = -8 / 2

slope = -4

Therefore, slope of the line that passes through points ( -10, -8 ) and ( -8, -16 ) is -4.

3 0

3 years ago

I need to find the simplest form of 88 ---- 90

hram777 [196]

Given

$\frac{88}{90}$

So,

$\frac{88}{90}=\frac{2\cdot44}{2\cdot45}=\frac{44}{45}$

So, the simplest form of 88/90 is 44/45

7 0

11 months ago

X² + y² = 34<br>x + y =8

Nataly [62]

Step-by-step explanation:

${x}^{2} + {y}^{2} = 34 \\ x + y = 8 \\ x = 8 - y \\ substitute \: x \: in \\ {x}^{2} + {y}^{2} = 34 \\ {(8 - 4)}^{2} + {y}^{2} = 34 \\ {(8 - 4) }^{2} = {y}^{2} - 16y + 64 \\ {y}^{2} - 16y + 64 + {y}^{2} = 34 \\ {2y}^{2} - 16y + 64 = 34 \\ {2y}^{2} - 16y + 64 - 34 = 0 \\ {2y}^{2} - 16y + 30 = 0 \\ 2 {y}^{2} - 6y - 10y + 30 = 0 \\ (2 {y}^{2} - 6y) - (10y + 30) = 0 \\ 2y(y - 3) - 10(y - 3) = 0 \\ (2y - 10)(y - 3) \\ 2y = 10 \\ y = \frac{10}{2} \\ y = 5 \\ or \\ y = 3 \\ if \: y = 5 \: \: x = 3 \\ if \: y = 3 \: \: x = 5$