Take any of the valid pairs of points, use the formula
rate of change = (y2-y1)/(x2-x1)
Say we use P1=(0,21.4), P2=(3,19)
x1=0, y1=21.4
x2=3, y2=19
Rate of change = (21.4-19)/(0-3)=2.4/(-3) = -0.8 sq. ft/in of liquid
Answer:
<u>The standard error of distribution for n = 4 is 5 and for n = 25 is 2.</u>
Step-by-step explanation:
1. Let's review the information given to us for solving the question:
Population mean = 72
Standard deviation = 10
Sample₁ = 4
Sample₂ = 25
2. For finding the standard error of the mean, we use the following formula:
Standard error = Standard deviation / √Size of the sample
Standard error for Sample₁ = 10/√4
<u>Standard error for Sample₁ = 10/2 = 5</u>
Now, let's find the standard error for Sample₂
Standard error for Sample₂ = 10/√25
<u>Standard error for Sample₂ = 10/5 = 2</u>
The probability of losing a data packet is 0.010.
Therefore the probability of successfully sending a data packet (not losing a data packet) is
p = 1 - 0.010 = 0.99
In 100 packet transmissions (independent events), the probability of success is
0.99¹⁰⁰ = 0.3660
The probability of losing a data packet is
1 - 0.366 = 0.6340
Answer:
The probability of resending a data packet is 0.6340
$23
Mathias has $20 in a savings account. The interest rate is
5% per year and is not compounded. How much will he have in 3 years?
They are terms<span> that contain the same variables raised to the same power. Only the numerical coefficients are different. In an expression, only </span>like terms<span> can be combined. We combine </span>like terms<span> to shorten and simplify algebraic expressions, so we can work with them more easily.</span>
