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likoan [24]
3 years ago
6

Whic flag has a special role in debuging

Computers and Technology
1 answer:
Zarrin [17]3 years ago
8 0

Answer: Interrupt flag

Explanation: In computer field , debugging field is referred as the process of finding the fault,error or bug and removing it from the software and hardware system. This process this carried out because this helps in avoiding the unexpected crash of the system due to the errors.

Flags are necessary for knowing about the source where the interrupt arises from and removing it, so interrupt flag is used for debugging .

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How Extreme Programming addresses Software Testing andevolution ?
kumpel [21]

Answer:

Extreme programming is a software development technique which is used to enhance software quality and it's response to ever changing customer requirements.

Testing

Testing is main focus in extreme programming.Extreme programming addresses testing in a way that if a minute testing can eliminate a bit of flaws, extensive testing can terminate a lot of flaws.

Evolution in Extreme programming is like this:-

Coding:-First programmers will code the problem.

Testing :- Testing is done to remove flaws.

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6 0
3 years ago
Write a python program to calculate the length of any string recursively​
Solnce55 [7]

Answer:

b

Explanation:

6 0
3 years ago
How many currencies do recognize?
klemol [59]
The United Nations currently recognizes 180 currencies that are used in 195 countries across the world the United States dollar is a popular currency and about 66 countries either peg their currency to the US dollar or use it as their currency
3 0
3 years ago
Please help me. i will mark you brailiest
Stolb23 [73]

Answer:

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3 0
3 years ago
Consider an error-free 64 kbps satellite channel used to send 512 byte data frames in one direction, with very short acknowledge
Vladimir [108]

Answer:

The answer is "2".

Explanation:

In the given question some information is missing, that is "The propagation time for satellite to earth" which is "270 milliseconds" so, the description to this question can be defined as follows:

Given values:

Bandwidth = 64 kbps

Data frames = 512 bytes  

Propagation Time (t​​​​​​p ) =270 ms

Change Bandwidth  kbps to bps:

1 kb= 1024 bytes

calculated bandwidth= 64 kbps = 64×1024 bps = 65536 bps

1 bytes = 8 bits

512 bytes = 512 × 8 =  4096 bits

Frame length = 4096 bits

Formula

Transmission time (T​​​​​​t) = Frame length /Bandwidth

Window size = 1+2a

where a = Propagation time/Transmission time

Calculate Transmission time:

Transmission time (T​​​​​​t) = 4096 / 65536

Transmission time (T​​​​​​t)= 625 m.sec

Calculate Window size:

Window size = 1+2(270/625)

Window size = 1+2(0.432)

Window size = 1+0.864

Window size = 1.864

Window size = 2

3 0
3 years ago
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