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likoan [24]
3 years ago
6

Whic flag has a special role in debuging

Computers and Technology
1 answer:
Zarrin [17]3 years ago
8 0

Answer: Interrupt flag

Explanation: In computer field , debugging field is referred as the process of finding the fault,error or bug and removing it from the software and hardware system. This process this carried out because this helps in avoiding the unexpected crash of the system due to the errors.

Flags are necessary for knowing about the source where the interrupt arises from and removing it, so interrupt flag is used for debugging .

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Student creates a Raptor program and uses the File Input and Output method to find the average of 5 test scores stored in a text
masya89 [10]

Answer:

The question was solved using an algorithm later translated to a flow chart that adds five scores giving the sum and calculating the average.

Explanation:

4 0
2 years ago
Technician A says that the reserve rating of a battery is the amount of steady current that a fully charged battery can supply f
Andre45 [30]

Answer:

Neither A nor B

Explanation:

<em>Reserve capacity</em> is the number of minutes that a new, fully charged battery can discharge continuously and maintain a terminal voltage equal to or greater than 1.75 volts per cell.

<em>An ampere-hour </em>is an electric charge unit and its abbreviation is Ah.

It measures the amount of electric charge flowing through a battery in the case that amount supplies a current of 1 amp for 1 hour.

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2 years ago
Find the inverse function of f(x)= 1+squareroot of 1+2x
Svetllana [295]

Answer:

Therefore the inverse function of  f(x)=1+\sqrt{1+2x} is \frac{x^2-2x}{2}

Explanation:

We need to find the inverse of function f(x)=1+\sqrt{1+2x}

Function Inverse definition :

\mathrm{If\:a\:function\:f\left(x\right)\:is\:mapping\:x\:to\:y,\:then\:the\:inverse\:functionof\:f\left(x\right)\:maps\:y\:back\:to\:x.}

y=1+\sqrt{1+2x}\mathrm{Interchange\:the\:variables}\:x\:\mathrm{and}\:y

x=1+\sqrt{1+2y}

\mathrm{Solve}\:x=1+\sqrt{1+2y}\:\mathrm{for}\:y

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+\sqrt{1+2y}-1=x-1

Simplify

\sqrt{1+2y}=x-1

\mathrm{Square\:both\:sides}

\left(\sqrt{1+2y}\right)^2=\left(x-1\right)^2

\mathrm{Expand\:}\left(\sqrt{1+2y}\right)^2:\quad 1+2y

\mathrm{Expand\:}\left(x-1\right)^2:\quad x^2-2x+1

1+2y=x^2-2x+1

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+2y-1=x^2-2x+1-1

\mathrm{Simplify}

2y=x^2-2x

\mathrm{Divide\:both\:sides\:by\:}2

\frac{2y}{2}=\frac{x^2}{2}-\frac{2x}{2}

\mathrm{Simplify}

y=\frac{x^2-2x}{2}

Therefore the inverse function of f(x)=1+\sqrt{1+2x} is \frac{x^2-2x}{2}

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2 years ago
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Answer:A

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