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3 years ago

Whic flag has a special role in debuging

Computers and Technology

1 answer:

Zarrin [17]3 years ago

8 0

Answer: Interrupt flag

Explanation: In computer field , debugging field is referred as the process of finding the fault,error or bug and removing it from the software and hardware system. This process this carried out because this helps in avoiding the unexpected crash of the system due to the errors.

Flags are necessary for knowing about the source where the interrupt arises from and removing it, so interrupt flag is used for debugging .

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Answer:

B. Specific and provided during the construction of the project, and the end of the project.

Explanation:

The feedback have to be specific and provided during the construction of the project, and at the end of the project.

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Answer:

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Explanation:

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4 years ago

What is the purpose of a macro in a word processor?

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3 years ago

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Art [367]

Using the knowledge of computational language in JAVA it is possible to write a code that Validate that the following code, which adds the methods var() and stddev() to Accumulator, computes both the mean and variance of the numbers presented as arguments to addDataValue()

<h3>Writting the code:</h3>

import java.util.*;

public class Accumulator {

private static double m;

private static double v;

private static double st;

private static double s[]=new double[5];

private static int N;

private static int count =0;

public static void main(String[] args) {

// TODO Auto-generated method stub

Random r = new Random();

System.out.println("hello world");

for(int i=0;i<5;i++) {

double randomvalue = r.nextDouble();

addDataValue(randomvalue);

}

for(int i=0;i<s.length;i++) {

System.out.println("dataValue:"+s[i]);

}

mean();

System.out.println("mean:"+m);

var();

System.out.println("variance:"+v);

stddev();

System.out.println("standard deviation:"+st);

}

public static void addDataValue(double value) { // addes data values to array

s[count]=value;

count++;

}

public static double mean() { // returns mean

double sum=0.0;

for(int i=0;i<s.length;i++) {

sum+=s[i];

}

m = sum/s.length;

return m;

}

public static double var() { //returns variance

double mm = mean();

double t = 0;

for(int i=0;i<s.length;i++) {

t+= (s[i]-mm)*(s[i]-mm);

}

v= t/(s.length-1);

return v;

}

public static double stddev() { // returnsn the stardard deviation

st= Math.sqrt(var());

return st;

}

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3 0

1 year ago

Brums [2.3K]

Answer:

is so good

Explanation:

7 0

3 years ago