Can somebody please help me !!!!!!

Mathematics

1 answer:

Katarina [22]3 years ago

5 0

So, looking at how many seniors there are, you can see that there are 35 of them. 25 are in sports, 5 are in music/drama, and 5 work. If you added them altogether, you get 35. Now, the chance of them being in sports is 25/35 chance/probability. You can simplify 25/35 because both of them are divisible by 5. 5 times 5= 25 and 7 times 5=35. Therefore, the answer is 5/7.

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lana66690 [7]

Answer:

$66 for 6 cars.

Step-by-step explanation:

This is a rather simple problem. To find the answer you must divide 44/4= 11. Now knowing that Chris earns $11 per car if you multiply 11x6= 66 you can find out Chris makes $66 for 6 cars.

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Is (1, 2) a solution to the inequality 6x - y> 3?

Lostsunrise [7]

Answer:

Yes.

Step-by-step explanation:

To find the answer we will put it into the equation, since x = 1 and y = 2 we will write it like this, 6(1) - 2 > 3. Since 6 x 1 = 6, we will now subtract 6 from 2 which equals 4. Therefore, the equation is correct because 4 is bigger than 3.

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2 years ago

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Answer:

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2 years ago

A helicopter leaves bristol and flies due east for 10 miles.Then the helicopter flies 8miles north before landing. What is the d

DedPeter [7]

Answer:

The distance of the helicopter from the bristol is approximately 12.81 miles

Step-by-step explanation:

Given:

Helicopter flies 10 miles east of bristol.

Then the helicopter flies 8 miles North before landing.

To find the direct distance between the helicopter and bristol.

Solution:

In order to find the distance of the helicopter from the bristol before landing, we will trace the path of the helicopter

The helicopter is first heading 10 miles east of bristol and then going 8 miles due north.

On tracing the path of the helicopter we find that the direct distance of the helicopter from the bristol is the hypotenuse of a right triangle formed by enclosing the path of the helicopter.

Applying Pythagorean theorem to find the hypotenuse of the triangle.

$Hypotenuse^2=Short\ leg^2+Shortest\ leg^2$