What is f(x) = 8x2 + 4x written in vertex form?
1 answer:
First of all, you need to complete the square of \(x\)
and this could be done as follows:
f(x)=8[x^2+0.5x]
=8[x^2 + 0.5x + (0.5/2)^2 - (0.5/2)^2]
=8[(x^2 + 0.5x +1/16) - 1/16]
=8[(x+0.25)^2 - 1/16]
And our parabola has the vertex form of this:
and according to the chart I attached, the vertex is (-0.25,-0.5)
Tell me <span>if there is any difficulty faces you!</span>
and this could be done as follows:
f(x)=8[x^2+0.5x]
=8[x^2 + 0.5x + (0.5/2)^2 - (0.5/2)^2]
=8[(x^2 + 0.5x +1/16) - 1/16]
=8[(x+0.25)^2 - 1/16]
And our parabola has the vertex form of this:
and according to the chart I attached, the vertex is (-0.25,-0.5)
Tell me <span>if there is any difficulty faces you!</span>
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