What is f(x) = 8x2 + 4x written in vertex form?
1 answer:
First of all, you need to complete the square of \(x\)
and this could be done as follows:
f(x)=8[x^2+0.5x]
=8[x^2 + 0.5x + (0.5/2)^2 - (0.5/2)^2]
=8[(x^2 + 0.5x +1/16) - 1/16]
=8[(x+0.25)^2 - 1/16]
And our parabola has the vertex form of this:
and according to the chart I attached, the vertex is (-0.25,-0.5)
Tell me <span>if there is any difficulty faces you!</span>
and this could be done as follows:
f(x)=8[x^2+0.5x]
=8[x^2 + 0.5x + (0.5/2)^2 - (0.5/2)^2]
=8[(x^2 + 0.5x +1/16) - 1/16]
=8[(x+0.25)^2 - 1/16]
And our parabola has the vertex form of this:
and according to the chart I attached, the vertex is (-0.25,-0.5)
Tell me <span>if there is any difficulty faces you!</span>
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Answer:
<h2>It is Theoretical probability.</h2>Step-by-step explanation:
Theoretical probability determines the likelihood of some incidents to happen.
Theoretical probability is the ratio between the total number of possible outcomes and the desired outcome.
Here, the desired outcome is getting a 2 that is only one desired outcome, where as total possible outcomes are 6. Here, the probability of getting a 2 is .
Empirical probability depends on observance. In the given question, nothing related to observance of the given incident has mentioned, hence it is not empirical probability.