What is f(x) = 8x2 + 4x written in vertex form?
1 answer:
First of all, you need to complete the square of \(x\)
and this could be done as follows:
f(x)=8[x^2+0.5x]
=8[x^2 + 0.5x + (0.5/2)^2 - (0.5/2)^2]
=8[(x^2 + 0.5x +1/16) - 1/16]
=8[(x+0.25)^2 - 1/16]
And our parabola has the vertex form of this:
and according to the chart I attached, the vertex is (-0.25,-0.5)
Tell me <span>if there is any difficulty faces you!</span>
and this could be done as follows:
f(x)=8[x^2+0.5x]
=8[x^2 + 0.5x + (0.5/2)^2 - (0.5/2)^2]
=8[(x^2 + 0.5x +1/16) - 1/16]
=8[(x+0.25)^2 - 1/16]
And our parabola has the vertex form of this:
and according to the chart I attached, the vertex is (-0.25,-0.5)
Tell me <span>if there is any difficulty faces you!</span>
You might be interested in
Octogon
sides=4
draw lines from the outside angles to the center so they form 8 equal triangle sections
find the area of each triangle and multiply by 8
area of triangle=1/2 base times height
base=4
the height is the distance from the center of one side of the octogon, to the center=5
so area=4 times 1/2 times 5=4 times 5=10
8 triangles so 8 times 10=80
the answer is 80cm^2
the diagram included below shows area for a pentagon
sides=4
draw lines from the outside angles to the center so they form 8 equal triangle sections
find the area of each triangle and multiply by 8
area of triangle=1/2 base times height
base=4
the height is the distance from the center of one side of the octogon, to the center=5
so area=4 times 1/2 times 5=4 times 5=10
8 triangles so 8 times 10=80
the answer is 80cm^2
the diagram included below shows area for a pentagon