Answer:
.7147
Step-by-step explanation:
Let P be the probability of 55 families having mean more than 17
P { (17-17.2)/ (2.5/√55) }
P(- 0.5933 )
= - .2765 [ From the z table ]
P be the probability of 55 families having mean less than 18
P { (18 -17.2)/ (2.5/√55) }
P( 2.3732 )
= .9912 [ From the z table ]
Probability of mean between 17 and 18
= .9912 - .2765
= .7147
What problems do you need help with?
Answer:
Number of candy left = 5
Step-by-step explanation:
Given:
Number of bags = 4
Number of candies in each bag = 8
Number of Gift boxes = 9
Find:
Number of candy left = ?
Computation:
Total number of candies = Number of bags × Number of candies in each bag
Total number of candies = 4 × 8
Total number of candies = 32
According to Euclid division lemma:
a = bq +r
32 = (3)(9) + Remainder
32 = 27 + Remainder
Remainder = 5
Number of candy left = 5
8.3,4.5,6.2,9.6,4.3,11.2,5.9,9.7,10.5
Mean:
To find mean you do the same as you would to find an average. Add up all of the numbers and divide by how many numbers are there. So,
8.3 + 4.5 + 6.2 + 9.6 + 4.3 + 11.2 + 5.9 + 9.7 + 10.5 = 70.2
Then divide by 9 since you have 9 numbers.
70.2 / 9 = 7.8
Median:
To find median you set up the data from least to greatest and cross out one number from each side until you are left with one number as the middle number.
4.3, 4.5, 5.9, 6.2, 8.3, 9.6, 9.7, 10.5, 11.2
4.5, 5.9, 6.2, 8.3, 9.6, 9.7, 10.5
5.9, 6.2, 8.3, 9.6, 9.7
6.2, 8.3, 9.6
= 8.3
Mode:
Mode is the most, meaning the number that appears the most in your set of data. In this case there is no mode because in your set there is no number that occurs more than once.
Hope this helps!
