Answer:
|x-3|+4 = 12
|x-3| = 12-4
|x-3| = 8
now solve for both positive and negative values
x - 3 = 8 | x - 3 = -8
x = 8 + 3 | x = - 8 + 3
x = 11 | x = -5
solution set : { 11, -5 }
Step-by-step explanation:
The point of elimination is to have one variable so example
3x + 2y = 4
7X + 3y = 5
1) Try to find a way to have one variable
7(3x + 2y = 4) ----> 21x + 14y = 28
-3(7x+ 3y = 5) -----> -21x -9y = -15
2) add
0 + 5y = 13
3) solve for the last variable
5y = 13
y = 13/5 = 2 3/5 = 2.8
4) Subsitute the variable to get the other one
3x + 2(2.8) = 4
3x + 5.6 = 4
3x = -1.6
x = 0.533333333 (continue)
The intersection would be 0.53 with a line above the 3 and 2.8. (0.5333 , 2.8)
Hope you understand!!
Answer:im not sure
Step-by-step explanation:
