Answer:
hello : all possible solutions for 2x+7<3x-5 is : x > 12
Step-by-step explanation:
calculate : x
2x+7<3x-5
2x - 3x <-7-5
-x < -12
all possible solutions for 2x+7<3x-5 is : x > 12
D. distribute the 3 to each term in the parentheses by multiplying.
3(2x - 6 - x - 1)^2 - 2 + 4x
3(x-7)^2 - 2 + 4x
3 (x^2 -14x +49) - 2 + 4x
3x^2 - 42x + 147 - 2 + 4x
Answer:
AM = 38
Step-by-step explanation:
Since A is the midpoint of JM, then
JA = AM = 6x - 4 , and
JA + AM = JM ← substitute values
6x - 4 + 6x - 4 = 9x + 13, that is
12x - 8 = 9x + 13 ( subtract 9x from both sides )
3x - 8 = 13 ( add 8 to both sides )
3x = 21 ( divide both sides by 3 )
x = 7
Hence
AM = 6x - 4 = (6 × 7) - 4 = 42 - 4 = 38