This "lessens" rivalry, since buyers become "less" price-sensitive.
Price sensitivity is how much the cost of an item influences customers' buying practices. In financial matters, price sensitivity is usually estimated utilizing the price elasticity of demand. For instance, a few buyers are not willing to pay even a couple of additional pennies per gallon for gas, particularly if a lower-valued station is adjacent.
Answer:
they have an opportunity to exploit network effects and positive feedback loops
Explanation:
The first mover advantage refers to competitive advantages that can be achieved by a firm that first enters a market or launches a new product first. E.g. Volkswagen has a first mover advantage in China because it was the first foreign car manufacturer to successfully a car factory there. Another type of first mover advantage would be the ones obtained by Apple for launching the first smartphone.
Network effects refers to a good or service becoming more valuable because more people purchase or use them, e.g. social media apps.
Positive feedback loops occurs when a company's output is used as a positive input in the productive system, e.g. when a company uses information gathered by customer service (CRM) to improve the products or services it offers.
Answer:
It will purchase 3 cans
total consumer surplus 0.70
Explanation:
the market price is 0.55
It will purchase up to three cans. the fourth can he is willing to purchase at 0.40 but the price is 0.55 so it won't trade for that one.
<u>consumer surplus:</u>
difference between the amounts he was willing to pay for each unit and the market price:
first can 0.95 - 0.55 = 0.40
second can 0.80 - 0.55 = 0.25
third can 0.60 - 0.55 = 0.05
total consumer surplus 0.70
Answer:
this is a cost minimization problem, but it is missing some numbers, so I looked for similar questions (see attached PDF):
minimization equation = 20x₁ + 22x₂ + 18x₃ (costs per ton)
where:
x₁ = mine I
x₂ = mine II
x₃ = mine III
the constraints are:
4x₁ + 6x₂ + x₃ ≥ 54 (high grade ore)
4x₁ + 4x₂ + 6x₃ ≥ 65 (low grade ore)
x₁, x₂, x₃ ≤ 7 (only 7 days per week)
using solver, the optimal solution is
2x₁, 7x₂, and 5x₃
a. The number of days Mine I should operate = <u>2 days
</u>
b. The number of days Mine Il should operate = <u>7 days
</u>
c. The number of days Mine III should operate = <u>5 days
</u>
d. The total cost of the operation for next week = <u>$284,000</u>
<span>When your ability to divide your attention is impaired the chances of being involved in a collision increase. A BAL as low as <u>0.02</u> has been shown to affect divided attention while driving.
BAL stands for Blood Alcohol Concentration Level. As the BAL increases, so does the level of impairment. The nearer the BAL is to 1, the more probable it is to meet an accident while driving. Thus, it is better to either ride a cab in going home or sleep in a safe place until the alcohol leaves the bloodstream.</span>
