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3 years ago

How do you find slope form

Mathematics

1 answer:

Mariana [72]3 years ago

5 0

do you mean simple form.if you did all you have to do is divide

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-1/2 (30x + 16) Help Please!<br> A. -27x - 7<br> B. -15x - 8<br> C. -18x - 9

Lady_Fox [76]

Answer:

A -(27x + 7)

B -(15x + 8 )

C -9(2x + 1 )

Step-by-step explanation:

-1/2 (30x + 16) = -15x-8

6 0

3 years ago

60 ☐ (72 ☐ 12) ☐ 34 = 44 Use the operations: ÷, +, and -

julia-pushkina [17]

Answer:

its 60 / (72/12) + 34 = 44. So divide, divide, add.

Step-by-step explanation:

First, solve the what's in the parentheses. 72/12 = 6.

60/6 = 10.

34+10 = 44.

3 0

4 years ago

The coach of a soccer team is holding tryouts and can only take 3 more players. There are 6 players trying out. How many differe

Elena-2011 [213]

$C(6,3)=\dfrac{6!}{3!3!}=\dfrac{4\cdot5\cdot6}{2\cdot3}=20$

5 0

3 years ago

Please help with this Calculus questions

Triss [41]

Answer:

$\int_{0}^{1}\left( - \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2 \right)du=\frac{193}{100}=1.93$ .

Step-by-step explanation:

To find $\int_{0}^{1}\left( - \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2 \right)du$ .

First, calculate the corresponding indefinite integral:

Integrate term by term:

$\int{\left(- \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2\right)d u}} =\int{2 d u} + \int{\frac{2 u^{4}}{5} d u} - \int{\frac{3 u^{9}}{2} d u}$

Apply the constant rule $\int c\, du = c u$

$\int{2 d u}} + \int{\frac{2 u^{4}}{5} d u} - \int{\frac{3 u^{9}}{2} d u} = {\left(2 u\right)} + \int{\frac{2 u^{4}}{5} d u} - \int{\frac{3 u^{9}}{2} d u}$

Apply the constant multiple rule $\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$

$2 u - {\int{\frac{3 u^{9}}{2} d u}} + \int{\frac{2 u^{4}}{5} d u} = 2 u - {\left(\frac{3}{2} \int{u^{9} d u}\right)} + \left(\frac{2}{5} \int{u^{4} d u}\right)$

Apply the power rule $\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$

$2 u - \frac{3}{2} {\int{u^{9} d u}} + \frac{2}{5} {\int{u^{4} d u}}=2 u - \frac{3}{2} {\frac{u^{1 + 9}}{1 + 9}}+ \frac{2}{5}{\frac{u^{1 + 4}}{1 + 4}}$

Therefore,

$\int{\left(- \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2\right)d u} = - \frac{3 u^{10}}{20} + \frac{2 u^{5}}{25} + 2 u = \frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)$

According to the Fundamental Theorem of Calculus, $\int_a^b F(x) dx=f(b)-f(a)$ , so just evaluate the integral at the endpoints, and that's the answer.

$\left(\frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)\right)|_{\left(u=1\right)}=\frac{193}{100}$

$\left(\frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)\right)|_{\left(u=0\right)}=0$

$\int_{0}^{1}\left( - \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2 \right)du=\left(\frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)\right)|_{\left(u=1\right)}-\left(\frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)\right)|_{\left(u=0\right)}=\frac{193}{100}$

6 0

3 years ago

The area of the rectangle is 54 units squared. Write and solve an equation to find x.

lord [1]

Answer: $x=5$

Step-by-step explanation:

The area of a rectangle can be found with the following formula:

$A=lw$

Where "l" is the length and "w" is the width.

In this case you can identify in the figure given in the exercise that:

$l=4x-2\\\\w=3$

You know that the area of that rectangle is the following:

$A=54$

Therefore, knowing those values, you can substitute them into the formula and then you must solve for "x" in order to find its value. You get that this is:

$54=(4x-2)(3)\\\\54=12x-6\\\\54+6=12x\\\\\frac{60}{12}=x\\\\x=5$

6 0

3 years ago