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erik [133]
3 years ago
6

Two boxes have the same volume. Box 1 has dimensions of 8 ft. by 4 ft. by 3 ft. Box 2 has dimensions of 12 ft. by 4ft by 2 ft. T

he material to make the boxes cost $3.00 per square foot. How much more does Box 2 cost than Box 1?
Mathematics
1 answer:
hram777 [196]3 years ago
3 0
You would have to find the surface areas of each box, which would be 8*4 *2, 8*3 *2, and 4*3 *2. That *3, would be the cost, and then surface area of 2 would be 12*4 *2, 12*2 *2, and 2*4 *2. That *3 would again be the cost to make the box. That all would be A=64 + 48 + 24, or 136*3 = $408 to make box A, and box B=96 + 48 + 16 = 160*3 = $480 to make box B. Therefore, box B, or $480 - $408 = $72 more.
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The sum of two numbers is 52. The greater number is 4 more than the smaller number. Which equation can be used to solve for the
Arisa [49]

Answer:

x+(x+4)=52

Step-by-step explanation:

Let's name the smaller number x.

The greater number would then be (x+4).

<em>The sum of two numbers means we are adding them together.</em>

<u>The equation we could then set up would be:</u>

x+(x+4)=52

<em>Now we can solve the equation to find the two numbers if needed.</em>

<u>Here is how:</u>

x+x+4=52

Combine like terms.

2x+4=52

Subtract 4 from both sides.

2x=48

Divide both sides by 2

x=24

The smaller number is 24.

24+4=28

The larger number is 28.

6 0
4 years ago
Pick all that apply the option answer in two minutes
iris [78.8K]

Answer: PQT and TUV

Step-by-step explanation:

8 0
3 years ago
70 POINTS!!!!!!!!!! Given: E, F, Q, D∈k(O),O ∈ ED, m∠DFQ = 10°, measure of arc EF = 28° Find: Angles of △EFQ
Likurg_2 [28]

Answer:

The measures of angles of triangle EFQ are

1) m\angle EFQ=100\°

2) m\angle FEQ=66\°

3) m\angle EQF=14\°

Step-by-step explanation:

step 1

Find the measure of arc QD

we know that

The inscribed angle is half that of the arc it comprises.

m\angle DFQ=\frac{1}{2}(arc\ QD)

substitute the given value

10\°=\frac{1}{2}(arc\ QD)

20\°=(arc\ QD)

arc\ QD=20\°

step 2

Find the measure of arc FQ

we know that

arc\ QD+arc\ FQ+arc\ EF=180\° ---> because ED is a diameter (the diameter divide the circle into two equal parts)

substitute the given values

20\°+arc\ FQ+28\°=180\°

arc\ FQ=180\°-48\°=132\°

step 3

Find the measure of angle EFQ

we know that

The inscribed angle is half that of the arc it comprises.

m\angle EFQ=\frac{1}{2}(arc\ QD+arc\ ED)

substitute the given value

m\angle EFQ=\frac{1}{2}(20\°+180\°)=100\°

step 4

Find the measure of angle FEQ

we know that

The inscribed angle is half that of the arc it comprises.

m\angle FEQ=\frac{1}{2}(arc\ FQ)

substitute the given value

m\angle FEQ=\frac{1}{2}(132\°)=66\°

step 5

Find the measure of angle EQF

we know that

The inscribed angle is half that of the arc it comprises.

m\angle EQF=\frac{1}{2}(arc\ EF)

substitute the given value

m\angle EQF=\frac{1}{2}(28\°)=14\°

5 0
4 years ago
I just need help on this is all
Cloud [144]
It’s the second answer. 2•10•2 + 2•10•3 + 2•2•3
4 0
3 years ago
Read 2 more answers
Un bloque de cemento de 10 Kg de masa cuelga de tres alambres, como se muestra en la figura. Si una bala de 1,2 kg viaja con una
Gala2k [10]

Step-by-step explanation:

Could you please type your question in English

Please!! I'm having a hard time understanding your question and I want to help

5 0
3 years ago
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