Answer:
Step-by-step explanation:
Given the system of two equations:
Add these two equations (left side add to left side and right side add to right side):
Substitute 
into the first equation:
Answer:
i don't know football but that's nice dude
11. 2x+3x+1=21
5x+1 =21
5x=20
x=4
TU= 2(4) which is 8
UB= 3(4)+1 which is 13
12. 4x-1 +2x-1=5x
6x-2=5x
-2=-1x
2=x
X=2
TU= 7
UB= 3
TB=10
Problem 13:
2x-8=x+17
2x=x+25
x=25
AB =42
BC=42
AC=84
Problem 14:
3x-31
-x+6
=
2x-37 for BC part now we solve for x
x+6=2x-37
6=x-37
43=x
So :
X=43
AB=49
AC=98
BC=49
The length of the unknown sides of the triangles are as follows:
CD = 10√2
AC = 10√2
BC = 10
AB = 10
<h3>Triangle ACD</h3>
ΔACD is a right angle triangle. Therefore, Pythagoras theorem can be used to find the sides of the triangle.
where
c = hypotenuse side = AD = 20
a and b are the other 2 legs
lets use trigonometric ratio to find CD,
cos 45 = adjacent / hypotenuse
cos 45 = CD / 20
CD = 1 / √2 × 20
CD = 20 / √2 = 20√2 / 2 = 10√2
20² - (10√2)² = AC²
400 - 100(2) = AC²
AC² = 200
AC = √200 = 10√2
<h3>
Triangle ABC</h3>
ΔABC is a right angle triangle too. Therefore,
Using trigonometric ratio,
cos 45 = BC / 10√2
BC = 10√2 × cos 45
BC = 10√2 × 1 / √2
BC = 10√2 / √2 = 10
(10√2)² - 10² = AB²
200 - 100 = AB²
AB² = 100
AB = 10
learn more on triangles here: brainly.com/question/24304623?referrer=searchResults
Answer:
20
Step-by-step explanation:
The water tank in the school hold 20 liters of water
One day it was 34 liters full
14 liters of water was used up
Therefore the quantity of water left can be calculated as follows
= 34-14
= 20
Hence 20 liters of water remains in the tank
