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inna [77]
2 years ago
14

Add - 3/x + 7y/x . -4y/2x -3 + 7y/x - 10y/x -3 + 7y/2x

Mathematics
1 answer:
yanalaym [24]2 years ago
3 0

Answer:

-\frac{3}{x} + \frac{7y}{x} = \frac{-3+ 7y}{x}

Step-by-step explanation:

Given

-\frac{3}{x} , \frac{7y}{x}

Required

Add

The statement can be interpreted as:

-\frac{3}{x} + \frac{7y}{x}

Take LCM

-\frac{3}{x} + \frac{7y}{x} = \frac{-3+ 7y}{x}

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he diagonal of a TV set is 52 inches long. Its length is 28 inches more than the height. Find the dimensions of the TV set. The
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Yup yea you got that yummy yummy
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3 years ago
Cody is cooking pancakes. The recipe calls for 5 3/10 cups of flour. He accidentally put in 8 1/4 cups. How many extra cups did
Eddi Din [679]

Answer:

59/20 cups

Step-by-step explanation:

5 3/10

8 1/4

Common denimainator  is 40

5 3/10 = 5 12/40

8 1/4 = 8 10/40

Now we can subtract:

330/40-212/40=118/40

118/40= 59/20 cups

Sorry if I spelled some words wrong

3 0
2 years ago
Find the zero of the following function: f(×)=(×-1)/(×-3)​
nlexa [21]

Answer:

\boxed{\sf \ \ x = 1 \ \ }

Step-by-step explanation:

Hello,

First of all we need to take x different from 3 as dividing by 0 is not allowed

then for x real different from 3

f(x)=0\\\\ \dfrac{x-1}{x-3}=0\\\\ x-1 = 0\\\\ x = 1

hope this helps

6 0
3 years ago
Read 2 more answers
What is the probability of getting two heads and 1 tail
aleksklad [387]
There is a 1/3 chance. Because there are 3 coins
8 0
3 years ago
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On a unit circle, the vertical distance from the x-axis to a point on the perimeter of the circle is twice the horizontal distan
swat32

Check the picture below.

since the vertical distance, namely the y-coordinate, is twice as much as the horizontal, then if the horizontal is "x", the vertical one must be 2x.

let's find the hypotenuse first.

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{x}\\ b=\stackrel{opposite}{2x}\\ \end{cases} \\\\\\ c=\sqrt{x^2+(2x)^2}\implies c=\sqrt{x^2+4x^2}\implies c=\sqrt{5x^2}\implies c=x\sqrt{5} \\\\[-0.35em] ~\dotfill

\bf sin(\theta )=\cfrac{\stackrel{opposite}{2~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}{\stackrel{hypotenuse}{~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ \sqrt{5}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{\cfrac{2}{\sqrt{5}}\cdot \cfrac{\sqrt{5}}{\sqrt{5}}\implies \cfrac{2\sqrt{5}}{(\sqrt{5})^2}\implies \cfrac{2\sqrt{5}}{5}}

5 0
3 years ago
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