<h3>
<u>Answer:</u></h3>

<h3>
<u>Step-by-step explanation:</u></h3>
A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.
The inequality given to us is :-

Let's plot a graph to see its interval . Graph attached in attachment .
Now we can see that the Interval notation of would be ,
![\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Corange%20%5Ctt%20%5Cpurple%7B%5Cleadsto%7Dy%20%5Cin%20%5B-2%2C-1%5D%20%7D%7D)
<h3>
<u>Hence</u><u> the</u><u> </u><u>standa</u><u>rd</u><u> </u><u>form</u><u> </u><u>of</u><u> </u><u>inequa</u><u>lity</u><u> </u><u>is</u><u> </u><u>y²</u><u>+</u><u>3y</u><u> </u><u>+</u><u>2</u><u> </u><u>≤</u><u> </u><u>0</u><u> </u><u>and</u><u> </u><u>the </u><u>Solution</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ineq</u><u>uality</u><u> </u><u>is</u><u> </u><u>[</u><u> </u><u>-</u><u>2</u><u> </u><u>,</u><u> </u><u>-</u><u>1</u><u> </u><u>]</u><u> </u><u>.</u></h3>
The area of a rectangle is length times width. Since a square's length is equal to its width, a square's area is equal to the length of one side times itself. So, reversed, the square root of the square's area gives the length of one side. In this case, the square root of 36 square centimeters is 6 centimeters. Again, since all four sides of a square are the same, its perimeter is equal to the length of one side times four. For a square with one side equal to 6 centimeters, the perimeter equals 24 centimeters.
Using the slip and slide method:
2x^2+5x-12
x^2+5x-24
(x+8)(x-3)
(x+8/2)(x-3/2)
(x+4)(2x-3)
Final answer: (2x-3)(x+4)
Answer:
Percent of increase. When it is more than the original amount, it is an increase. When it is less, it is a percent of decrease
Step-by-step explanation: