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maxonik [38]
3 years ago
5

60 is what percent of 90?

Mathematics
2 answers:
Rudiy273 years ago
3 0

Answer:

\boxed{66.67\%}

Step-by-step explanation:

\frac{60}{90}

=\frac{2}{3}

\approx 66.67\%

60 is <u>66.67</u> percent of 90.

JulsSmile [24]3 years ago
3 0
  • Answer:

66,(6) %

  • Step-by-step explanation:

90 ............... 100%

60 ....................X%

X = 60×100/90 = 600/9 = 66,(6) %

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Which represents the inverse of the function f(x)=4x?
Juliette [100K]

Answer:

h(x) = \frac{1}{4}x

Step-by-step explanation:

Suppose h is the inverse of f then

f(x) = y ⇔ h(y) = x

f(x) = y ⇔ 4x = y ⇔ x = y/4

and since x = h(y) then h(y) = y/4

then we can write :

h(x) = \frac{x}{4}

______________________

:)

8 0
3 years ago
The length of Peter's rectangular living room is 6 meters and the distance between opposite corners is 7 meters. What is the wid
padilas [110]

Answer:

3.6 m

Step-by-step explanation:

Given that :

Length of room = 6

Distance between opposite corners = 7

Width of room :

Using Pythagoras rule:

Opposite ²= hypotenus² + adjacent²

From. The diagram attached :

w² = 7² - 6²

w² = 49 - 36

w² = 13

w = 3.605

w = 3.6 m

7 0
2 years ago
What is the greatest common factor of 48 and 64?
aleksklad [387]

Answer:

The GCF of 48 and 64 is 16

Step-by-step explanation:

To figure out GCF, you make a list of all the prime factors, pick out the numbers they have in common, and multiply them together.  In this case:

48:  2 x 2 x 2 x 2 x 3

64: 2 x 2 x 2 x 2 x 2 x 2

They have four 2's in common, so you multiply 2 x 2 x 2 x 2 =16

8 0
3 years ago
A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6
ddd [48]

Answer:

The population of bacteria after 6 days is 2,313.06

Step-by-step explanation:

Given as :

The initial population of bacteria = i = 1,000 bacteria

The growth rate of bacteria per day = 15%

Let The population of bacteria after 6 days = f

The time period of growth = 6 days

<u>Now, According to question</u>

The population of bacteria after 6 days = initial population × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, f = i × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, f = 1000 × (1+\dfrac{\textrm 15}{100})^{\textrm 6}

Or, f = 1000 × (1.15)^{6}

Or, f = 1000 × 2.31306

∴  f = 2,313.06

So,The population of bacteria after 6 days = f = 2,313.06

Hence,The population of bacteria after 6 days is 2,313.06  Answer

3 0
3 years ago
If we increase the number 100 by 10% and then reduce the resulting number by 20% what would the answer be plz show how u did it
Readme [11.4K]

Answer:

88

Step-by-step explanation:

The original number ⇒ 100

100 is increased by 10%

The result is 20% reduced.

Calculate increase.

100 × (1 + 10%)

100 × (1.1)

= 110

Calculate decrease.

110 × (1 - 20%)

110 × 0.8

= 88

4 0
3 years ago
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