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Kruka [31]
3 years ago
11

A 26-foot long ladder is leaning against a building at a 60 degree angle with the ground. Which of the following equations can y

ou use to find the height of the building, h? What is the approximate height of the building? Round to the nearest tenth of a foot. feet
Mathematics
2 answers:
Sati [7]3 years ago
4 0

Answer:

22.5 feet (to the nearest tenth).

Step-by-step explanation:

The equations have not been given but still the question can be solved. The ladder lying with a building makes a right angled triangle, in which the ladder is the hypotenuse, the building is the perpendicular, and the ground is the base. The length of the ladder (hypotenuse) is 26 feet and the angle with the ground is 60 degrees. The required length to be found is the length of the building (perpendicular). So the following formula will be used:

sin θ = Perpendicular/Hypotenuse.

Substituting in the equation gives:

sin60 = p/26.

p = 26*sin60.

p = 22.5 (to the nearest tenth).

The approximate height of the building is 22.5 feet!!!

Makovka662 [10]3 years ago
4 0

Answer:

csc(60°) = 26/h

22.5 ft

Step-by-step explanation:

its the right answer :)

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16 2/3% of what number is 72
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Answer:

The number is 4321

Step-by-step explanation:

Let the number be x

16 2/3% = (16x3+2)/3 % = 50/3 %

50/3 % of X = 72

50/300 x X =72

X=(72 x 300)/50

X=21600/50

X=4321

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3 years ago
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viva [34]

Answer:

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Step-by-step explanation:

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3 years ago
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The variables x and y vary inversely If x=5 when y=12, then find the value of x when y=32
Vilka [71]

Answer:

x=15/8

Step-by-step explanation:

Inverse variation is given by

xy = k

Substituting x=5 and y=12

5*12 = k

60 =k

Our original equation is xy = 60

Now let y=32

x*32 = 60

Divide each side by 32

32x/32 = 60/32

Divide top and bottom by 4

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4 0
3 years ago
Carlos is using the quadratic formula to find the solutions of y=3x^2-5x-2. Which of the following will simplify to the correct
Nana76 [90]

Answer:

Fx=\frac{5\pm\sqrt{25+24} }{6}

Step-by-step explanation:

A quadratic equation in one variable given by the general expression:

ax^2+bx+c

Where:

a\neq 0

The roots of this equation can be found using the quadratic formula, which is given by:

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

So:

y(x)=3x^2-5x-2=0

As you can see, in this case:

a=3\\b=-5\\c=-2

Using the quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}=\frac{-(-5)\pm\sqrt{(-5)^2-4(3)(-2)} }{2(3)}=\frac{5\pm\sqrt{25+24} }{6}

Therefore, the answer is:

Fx=\frac{5\pm\sqrt{25+24} }{6}

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Crazy boy [7]
2x squared would be you final answer
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3 years ago
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