Answer:
Step-by-step explanation:
<A = 180 - (63+90)
<A = 180 - 63 - 90
<A = 180 - (63+45+<B )
<A = 180 -63 -45 -<B
(0,15)(1,19)
slope = (19 - 15) / (1 - 0) = 4
y = mx + b
slope(m) = 4
(0,15)...x = 0 and y = 15
sub
15 = 4(0) + b
15 = b
y = 4x + 15....so ur rule is : F(s) = 4s + 15
A circle can be circumscribed about a quadrilateral if and only if the opposite angles of the quadrilater sum up to 180.
This is not the case, so you can't circumscribe a circle about the quadrilateral.
Answer:
I didn't understand what you mean
Answer:
37.5%
Step-by-step explanation:
