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3 years ago

7

What segment is an altitude of triangle ABC?

1 answer:

sergejj [24]3 years ago

6 0

The best and most correct answer among the choices provided by your question is the third choice.

Line segment BD is the altitude of triangle ABC.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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Find the distance between points J and Q.

GarryVolchara [31]

Answer:

The answer is 20

Step-by-step explanation:

From the graph it shows that J is located at point 15, and Q is located at point 35

If we move 20 units from point J to point Q, we land at point Q, making it the distance they are from one another.

8 0

3 years ago

Please help me in this one!!

olga2289 [7]

A^3
a to the power of three

6 0

2 years ago

Read 2 more answers

Lil makes $3.51 am hour more than Noah. Both of them worked for 42 hours on a project. Together, they made $1147.02 what is Noah

finlep [7]

Answer:

999.60

Step-by-step explanation:

$3.51 times 42 is 147.42 and 1147.02 minus 147.42 is $999.60

TBH this might not be right I'm not great at math buuut- heeeyy

8 0

3 years ago

Is the square root of 65 rational or irrational?

wlad13 [49]

Step-by-step explanation:

$\sqrt{65}$

As it can't be expressed in the form p/q, where q is not equal to 0,

<em><u>Hence</u></em><em><u>,</u></em>

<em><u>square</u></em><em><u> </u></em><em><u>root</u></em><em><u> </u></em><em><u>65</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>an</u></em><em><u> </u></em><em><u>irrational</u></em><em><u> </u></em>

3 0

2 years ago

If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers

seraphim [82]

Answer:

a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

$\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}$

<h2>Simplify it in steps:</h2>

<h3>Step 1</h3>

Bring both fractions into common denominator:

$\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}$

<h3>Step 2</h3>

Simplify:

$\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =$

$\dfrac{4\sqrt{14} }{7-4} =$

$\dfrac{4}{3} \sqrt{14} }$

<h3>Step 3</h3>

Compare the result with given expression to get:

a = 4/3 and b = 0

4 0

2 years ago