The derivative is the gradient.
At any local Max's or min's the derivative graph will cut the x axis.
For example a graph x^2
The derivative will have a positive gradient as the gradient is increasing at the lower values then at x=0 the gradient is 0 so the derivative graph will pass the point (0,0). Remember that the derivative graph will be linear.
To get more detail find the points the graph crosses the x axis and put into for a(x-q)(x-p)=0 you will have to solve for 'a' by finding a point on the graph and substituting it in. Then you can find the derivative of that function and graph it
I think the answer is sas
Answer:
y=0.5x+40
Step-by-step explanation:
Copy the equation.
x-2y=8
Subtract x from both sides.
-2y=-x-8
Divide both sides by -2.
y=0.5x+4
Now we know the slope is 0.5.
Any line with a slope of 0.5 will be perpendiculr to the original line.
One that you can use is y=0.5x+40.
First you set up an equation using a variable:
x + 5x = 90° (complementary angles = 90°)
6x = 90
x = 15 (also the measure of the smaller angle)
now plug in x to find the larger angle:
5(15) = 75°
