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PtichkaEL [24]
3 years ago
13

32/64= in lowest fraction

Mathematics
1 answer:
MrRa [10]3 years ago
5 0
The answer is 1/2 and as a decimal it is 0.5
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A line includes the points (4, 8) and (3, 5). What is its equation in slope-intercept form? Write your answer using integers, pr
stich3 [128]

Answer:

A line includes the points (4, 8) and (3, 5) whose equation in slope-intercept form will be :

y=3x-4

Step-by-step explanation:

The point slope form: (x_1,y_1) and(x_2,y_2)

(y-y_1)=m(x-x_1)

where : m = Slope of the line

m=\frac{y_2-y_1}{x_2-x_1}

A line includes the points (4, 8) and (3, 5).The equation of the line will be:

m=\frac{5-8}{3-4}=3

(y-8)=3\times (x-4)

y-8=3x-12

y=3x-4

(y=mx+c), where c is intercept at y axis.

The above equation represents slope-intercept form of the line.

6 0
3 years ago
A retailer purchased soccer cleats for $18 from a wholesaler.The retalier sells the cleats for $32.What is the markup rate?Round
Tamiku [17]

Answer:

0.7bar

Step-by-step explanation:

(32-18)/18

=14/18

=7/9

=0.7bar

4 0
2 years ago
Read 2 more answers
An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de
Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have:

P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have

P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453

The sum of the probabilities is

P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981

8 0
3 years ago
Please answer this I will give u​
satela [25.4K]

Answer:

Step-by-step explanation:

The 3 angles must add up to 180. So

6x + 4x + 2x = 180

12x = 180

x = 15

Plug this into all the angles and you have your answers

5 0
3 years ago
Read 2 more answers
Ellis can spend up to $40 for gasoline and a carwash at a service station. The carwash will cost $6.00, and gasoline costs $4.50
natta225 [31]

Solving the inequality for g

Move the 6 over by subtraction and you have:

4.5g ≤ 34

Then divide each side by 4.5

g = 7.55555

So Ellis can purchase at lease 7 gallons but not 8  (D)

5 0
3 years ago
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