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vagabundo [1.1K]
2 years ago
14

23.

Mathematics
1 answer:
Crazy boy [7]2 years ago
3 0

Answer:

The number that cannot be the largest possible 6-digit number is;

(D) AAABCB

Step-by-step explanation:

From the question, we have;

A, B, and C = Distinct digits, therefore, A ≠ B ≠ C

The number of digits in the number to be formed = 6 digits

The number of 'A' in the number to be formed = 3

The number of 'B' in the number to be formed = 2

The number of 'C' in the number to be formed = 1

We have;

When A > B > C

The largest possible number = AAABBC

When C > A > B

The largest possible number = CAAABB

When B > A > C

The largest possible number = BBAAAC

When A > C > B

The largest possible number = AAACBB

Therefore, given that when A > B > C, the largest possible number = AAABBC, we have;

AAABBC > AAABCB, because B > C, therefore, within the tens and unit of the two 6 digit numbers, we have, BC > CB

∴ AAABBC > AAABCB and <u>AAABCB</u>, cannot be the largest possible 6-digit number

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When rounding here are the rules
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Now for #14, think about the rules.
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  2. If you round it to the nearest tenth, you get 7.0.
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Ok basically it is saying, it rounds up to 7.  So what would be the number that would round UP to 7?  That would be 6.  I'm rounding UP because it says it is the LEAST number that fits the clues. 
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3 years ago
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