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sleet_krkn [62]
4 years ago
15

14. Two parallel lines l and m are intersected by a transversal t. If the interior angles on same side of transversal are (2x−8)

o and (3x−7)o . Find the measure of these angles.
Mathematics
1 answer:
nlexa [21]4 years ago
8 0

Answer:

70° and 110°

Step-by-step explanation:

It is given that, two parallel lines l and m are intersected by a transversal t.

The interior angles on same side of transversal are (2x−8)° and (3x−7)°.

We need to find the measure of these angles.

We know that, the sum of interior angles of the same side of the  transversal is equal to 180°. So,

(2x−8)° + (3x−7)° = 180°

⇒ 5x-15=180°

⇒5x=180°+15

⇒5x=195

⇒x=39

Put x = 39 in (2x−8)°,

(2x−8)° = (2(39)-8)°

=70°

Again put x = 39 in (3x−7)°,

(3x−7)° = (3(39)-7)°

=110°

So, the measure of these angles are 70° and 110°.

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See attachment for complete question

Required

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Term \to 4 * 8^n ---- n

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Solving (c):

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2 \to 2 * 3^0 --- 0

6 \to 2 * 3^1 ---- 1

18 \to 2 * 3^2 --- 2

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Term \to 2 * 3^n ---- n

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75 \to 3 * 5^2 --- 2

375 \to 3 * 5^3 ---- 3

1875 \to 3 * 5^4 ---- 4

For the nth term, the expression is:

Term \to 3 * 5^n ---- n

So, the summation is:

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

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