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3 years ago

(GR.7MATH)

Mathematics

2 answers:

TEA [102]3 years ago

8 0

Answer:

dcc

Step-by-step explanation:

aajajaja

Ronch [10]3 years ago

5 0

Yyghuhggugguvcyvgvgyvuvg

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5. Which graph best represents the equation y=-2x-2?

Alenkasestr [34]

Graph best represents the equation y=-2x-2
Answer-D

8 0

3 years ago

Read 2 more answers

Please solve this<br>20×10=

Vadim26 [7]

Answer:

20 × 10 = 200

Step-by-step explanation:

Multiply 2 × 1 = 2 and then add the two zeros onto the end to get 200.

3 0

3 years ago

Bennett purchase some beef and some chicken for a family barbecue the beef cost was $6.30 per pound and the chicken cost $4.60 p

Ivenika [448]

Answer: He bought 7 pounds of chicken and 5 pounds of beef

Step-by-step explanation: We shall start by assigning letters to the unknown variables. Hence, let b represent a pound of beef and let c represent a pound of chicken. If Bennett bought a total of 12 pounds of meat, then we can express this as

b + c = 12

Then if he spent a total of $63.7 on both types of meat, we can write it out as

6.3b + 4.6c = 63.7

We now have a pair of simultaneous equations, which are

b + c = 12 --------(1)

6.3b + 4.6c = 63.7 --------(2)

In equation (1) we shall make b the subject of the equation

b = 12 - c

We now substitute for the value of b into equation (2)

6.3(12 - c) + 4.6c = 63.7

75.6 - 6.3c + 4.6c = 63.7

We collect like terms and we now have

-1.7c = -11.9

Divide both sides of the equation by -1.7

c = 7.

Having found the value of c, we can now substitute for the value of c into equation (1)

b + c = 12

b + 7 = 12

Subtract 7 from both sides of the equation

b = 5.

Therefore, Bennett purchased 7 pounds of chicken and 5 pounds of beef.

6 0

4 years ago

Can someone pleaseeee help

Darya [45]

Answer:

Yes

Step-by-step explanation:

I hope this is correct and have a great day

6 0

3 years ago

Read 2 more answers

Consider the following statement There are real numbers and such that Va+ V + b in the box below, as an ordered, comma that sati

Sever21 [200]

Answer:

a=0, b=16, of the pair (0,16)

Step-by-step explanation:

You want to prove the following: There are real numbers a and b such that $\sqrt{a+b}=\sqrt{a}+\sqrt{b}$

So, to prove this, it is enough to find a pair (a,b) of real numbers for which the equation holds true. There are infinite of such pairs, but one example is (0,16). Indeed:

$\sqrt{a+b}=\sqrt{0+16}=\sqrt{16}=4=0+4=\sqrt{0}+\sqrt{16}=\sqrt{a}+\sqrt{b}$

In fact, (0,m) or (n,0) ara valid pairs, for nonnegative numbers m,n. Even more is true; these are the only pairs which satisfy the equation.

3 0

4 years ago