you draw two cards from a well-shuffled deck of 52 cards. After you draw the first card, you do not replace it in the deck. What
is the probability of P(get ace of spades on first draw and get queen of hearts second draw?
1 answer:
52 total cards...
P(ace of spades on first draw) = 1/52
without replacing
P(queen of hearts) = 1/51
P(both events happening) = 1/52 * 1/51 = 1/2652 <==
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Your equation should be
$4(40 tickets) + $5(X) = $400
160 +5x = 400
-160 -160
0 5x = 340
divide both sides by 5
5x/5 = 340/5
x = 68
so they need to sell 68 tickets at the door.
4(40) + 5(68) = 400
160 + 340 + 400
400 + 400
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Answer:
using pi *r^2 *h
volume = 2614.14 cubic ft
2/3b + 19 = 35
-19 -19
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2/3b = 16
÷2/3 ÷2/3
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Step-by-step explanation:

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