Question

the sides of one right triangle are 6,8 and 10.the sides of another right triangle are 10,24 and 26.determine if the triangle are similar.if so, what is the ratio for their corresponding sides?what is the ratio of their perimeters and their area measure?

Answer 1

So the ratio must be the same for the triangle to be the same
smallest side of 1 right triangle to smalles side of other right trigle shoudl be same as largest  side of 1 right trignale to largest side of other right triangle and also middle side


6:10 should equal 10:26 should equal 8:24
treat as fraction
6/10=10/26=8/24?
3/5=5/13=1/3
we know that 3/5 is not equal to 1/3 so they are NOT SIMILAR

ratios are
3:5
1:3
5:13


the perimiter of the smaller is 6+8+10=24
perimiter of larger is 10+24+26=60
ratio of perimiters larger to smaller is 60:24=5:2

area is 1/2 base times height
longest side=hypotonuse
therefor other 2 sides must be base and height

area of smaller=8 times 6 times 1/2=24

area lf larger=10 times 24 times 1/2=120
ratio of larger ot smaller is 120:24=5:1



not similar


ratio of perimiter larger to smaler=5:2

ratio oif area larger to smaller=5:1