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2 years ago

Need an answer for this question

Mathematics

1 answer:

Natasha_Volkova [10]2 years ago

5 0

Answer: f(-2)=6.
Explanation: Since -2 is less than 1 you plug it into the top equation for -(-2)+4 = 2+4 =6

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Janet is 48 in tall and Lucy her younger sister is 32 in tall at 2:30 in the afternoon Lucy's Shadow extends 34 in how far does

Elis [28]

Janet is 50inches tall.

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3 years ago

Solve for x using the given diagram

blagie [28]

Answer:

Step-by-step explanation:

Look a t the picture.

The triangles on the picture are similar.

Therefore the sides are in proportion:

$\dfrac{8x}{10}=\dfrac{4}{5x}$ <em>cross multiply</em>

$(8x)(5x)=(4)(10)$

$40x^2=40$ <em>divide both sides by 40</em>

$x^2=1\to x=\sqrt1\\\\x=1$

7 0

3 years ago

PLEASE HELP

elixir [45]

Answer:

Ratio states that it shows the relative sizes of two or more values.

i,e a to b or a: b or $\frac{a}{b}$

(1)

Given the statement: A zoo has 17 monkeys and 12 chimpanzees

Write this situation in three ways, comparing the first quantity to the second quantity.

By definition of ratio:

Ratio in three ways are:

17 to 12

17 : 12

$\frac{17}{12}$ or we can write this as 17 over 12.

therefore, Option B is correct.

(2)

As per the statement: In Largo City, about one in every nine homes contains four televisions

Write this situation in three ways in the form of ratio, comparing the first quantity to the second quantity.

By definition of ratio:

Ratio in three ways are:

4 to 9

4 : 9

$\frac{4}{9}$

therefore, only options C is correct.

(3)

write three ratios for 7 over 35

By definition of ratio;

We have;

$\frac{7}{35}$

Divide both numerator and denominator by 7 we have;

$\frac{1}{5}$ .....[A]

⇒ $\frac{7}{35} =\frac{1}{5}$

Multiply both numerator and denominator by 2 in A we get;

$\frac{1}{5} = \frac{1 \times 2}{5 \times 2} = \frac{1}{10}$

Similarly,

Multiply both numerator and denominator by 3 in A, we get

$\frac{1}{5} = \frac{1 \times 3}{5 \times 3} = \frac{3}{15}$

Therefore, 3 ratios equal to 7 over 35 are;

$\frac{1}{5}$ or we can write it as one-fifth

$\frac{2}{10}$ or two -tenths

$\frac{3}{15}$ or three over fifteen

hence, Option D is correct.

(4)

Given the statement: Jake sold 28 tickets to the school fair, and Jeanne sold 21 tickets

Number of ticket Jake sold = 28 ticket.

Number of ticket Jeanne sold = 21 ticket.

To find: Number of ticket Jeanne sold to number of ticket Jake sold.

By definition of ratio

⇒ $\frac{21}{28}$

Therefore, the ratio in simplest form is, $\frac{21}{28}$

6 0

3 years ago

Read 2 more answers

Solve the inequality.<br> 6+x>56+x>5

weqwewe [10]

Answer:

X>50

X>-51

Step-by-step explanation:

6+x>56

56+x>5

separate the equation into different equations by the sign

I) 6+x>56

x>56-6

x>50

ii) 56+x>5

x>5-56

x>-51

4 0

2 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

3 years ago