Here's our equation.
We want to find out when it returns to ground level (h = 0)
To find this out, we can plug in 0 and solve for t.
So the ball will return to the ground at the positive value of
seconds.
What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!
Answer:
Step-by-step explanation:
T=V/6-5
T+5=V/6
6(T+5)=V
V=6T+30
Answer: The correct factors are
(x-1) and (x+2)
Step-by-step explanation:
Step one :
To factorize the equation
x²– x – 2=0
First we look for numbers that when multiplied will result to the constant term and when added will result to the second term (1x, - 2x)
Step two :
We replace the second term with these factors we have
x²–(x-2x)–2=0
x²–x+2x–2=0
Factoring the expression we have
x(x–1)+2(x–1)=0
Hence the factors will be
(x-1) and (x+2)
Since you need a little bit of trigonometry to solve this problem,
I'm pretty sure you've had a little bit of trigonometry in class before
you were assigned to solve this problem.
-- The shaded triangle comes from taking the equilateral triangle and
either folding it in half or cutting it in half.
-- The base that the new triangle is standing on is 1/2 the base of the
equilateral triangle, so it's 7 cm long.
-- The acute angle at the right end of the base is the same as it was in
the equilateral triangle . . . 60 degrees.
-- The tangent of 60 degrees is (opposite side)/(adjacent side) = x / 7 cm
tan(60) = x/7
-- Multiply each side of this little equation by 7 : 7 tan(60) = x
If you don't have the tangent of 60 degrees in your pocket, you can
find it with your calculator. Multiply it by 7, and Shazam, you know 'x' .
