Answer:
$60.48
Step-by-step explanation:
hope this helps!!
Remember these two combinations: logab=loga+logb, log(a/b)=loga-logb
3logx=logx^3
(1/2)log(x+2)=log(x+2)^(1/2)
2log(z-4)=log(z-4)^2
so the given expression can be combined into log{[(x^3)(z-4)^2]/(x+2)^(1/2)}
Answer:
Step-by-step explanation:
If A is in between Y and Z, then;
YA+AZ = YZ
Given.
YA = 14x,
AZ = 10x and
YZ = 12x + 48
Substitute into the formula
14x+10x = 12x+48
Find x;
24x = 12x+48
24x-12x = 48
12x = 48
x = 48/12
x = 4
Get AZ
AZ = 10x
AZ =10(4)
AZ = 40
The correct answer is the first one(a): To get the system B,..., the first equation multiplied by 4...
Explanation:
1. Let us first multiple the first equation in System A with 4, we would get:
4(2x - y) = 4 * 3
=> 8x - 4y = 12 --- (A)
Now add the equation (A) and the second equation of System A:
8x - 4y = 12
3x + 4y = 10
------------------
11x = 22
Hence,
System B:
2x - y = 3
11x = 22
-i
Answer:
6/8
Step-by-step explanation:
I answered this math question on edge and 100%.
