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Montano1993 [528]
3 years ago
10

WILL GIVE BRAINLIEST TO 1ST 4x+188=6x+216

Mathematics
1 answer:
Ulleksa [173]3 years ago
6 0

Answer:

x = -14

Step-by-step explanation:

Let's solve your equation step-by-step.

4x + 188 = 6x +216

Subtract 6x from both sides:

4x + 188 - 6x = 6x + 216 - 6x

-2x + 188 = 216

Subtract 188 from both sides:

-2x + 188 - 188 = 216 - 188

-2x = 28

Divide both sides by two:

\frac{-2x}{-2}=\frac{28}{-2}

x = -14

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Simplify 5x(3x^2+2x-3)
Tcecarenko [31]

Answer:

15x^3 +10x^2 - 15x

Step-by-step explanation:

Hello!

Use the distributive property and multiply like terms.

<h3>Simplify</h3>
  • 5x(3x^2 + 3x - 3)
  • 5x(3x^2) + 5x(2x) + 5x(-3)
  • 15x^3 +10x^2 - 15x

The simplified form is 15x^3 +10x^2 - 15x.

4 0
2 years ago
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If f(x) =1/x and g(x) = x - 2 what is f(g(x)) when X = 1​
Fed [463]

Answer:

f(g(x)) = -1

Step-by-step explanation:

f(x) =  \frac{1}{x}  \\  \\ g(x) = x - 2 \\  \\  \implies \: f(g(x)) =  \frac{1}{x - 2}  \\  \\  \implies \: f(g(1)) =  \frac{1}{1 - 2} \\  \\  \implies \: f(g(1)) =  \frac{1}{ - 1} \\  \\  \implies \: f(g(1)) =   - 1

8 0
2 years ago
Can someone please help me!
Alina [70]

Answer:

84

Step-by-step explanation:

k(x+6)= 4x²+20

k(10)= k(4+6)= 4*4²+20= 64+20= 84

8 0
3 years ago
Which piece of additional information can be used to prove △CEA ~ △CDB?
Slav-nsk [51]

<u>Answer-</u>

<em>The correct answer is</em>

<em>∠BDC and ∠AED are right angles</em>

<u>Solution-</u>

In the ΔCEA and ΔCDB,

m\angle BCD=m\angle ACE

As this common to both of the triangle.

If ∠BDC and ∠AED are right angles, then m\angle E=90=m\angle D

Now as

∠BCD = ∠ACE and ∠BDC = ∠AED,

∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)

Then, ΔCEA ≈ ΔCDB

Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.


5 0
3 years ago
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What are the zeros<br>(x+12)^2=0
wariber [46]
(x+12)^2 = 0

x + 12 = 0

x = - 12

4 0
3 years ago
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