2 years ago

What is the factored form of X^9+27 A (x^3-3)(x^6+3x^3+9) B(x^3+3)(x^6-3x^3+9) C(x-3)^3(x^6+3x^3+9) D(x+3)^3(x^6-3x^3+9)

Mathematics

1 answer:

irinina [24]2 years ago

5 0

Answer:

Step-by-step explanation:

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1 year ago

Solve for s.

Radda [10]

Answer:

s = 5/6, s = 3

Step-by-step explanation:

(6s - 5)(s - 3) = 0

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1. ...........

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2 years ago

Solve c= 8a-3b for a

Vesnalui [34]

Answer:

(c+3b)/8 = a

Step-by-step explanation:

c= 8a-3b

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3 years ago

What is the factored form of X^9+27 A (x^3-3)(x^6+3x^3+9) B(x^3+3)(x^6-3x^3+9) C(x-3)^3(x^6+3x^3+9) D(x+3)^3(x^6-3x^3+9)​

What is the factored form of X^9+27 A (x^3-3)(x^6+3x^3+9) B(x^3+3)(x^6-3x^3+9) C(x-3)^3(x^6+3x^3+9) D(x+3)^3(x^6-3x^3+9)