<span> a • (6ab2 + 2ab - 2a - 3b2 + 4b)
</span>
Step by step solution :<span>Step 1 :
</span><span>Equation at the end of step 1 :</span> (3ab • (2ab + 2a - b)) - 2a • (2ab + a - 2b)
<span>Step 2 :</span><span>Equation at the end of step 2 :</span> 3ab • (2ab + 2a - b) - 2a • (2ab + a - 2b)
<span>Step 3 :</span><span>Step 4 :</span>Pulling out like terms :
<span> 4.1 </span> Pull out like factors :
<span> 6a2b2 + 2a2b - 2a2 - 3ab2 + 4ab</span> =
<span> a • (6ab2 + 2ab - 2a - 3b2 + 4b)</span>
Final result :<span> a • (6ab2 + 2ab - 2a - 3b2 + 4b)</span>
Only the second set of measures qualifies as angle measures of a triangle. Angles 25°, 130°, 25°
Step-by-step explanation:
- Step 1: To find whether angles qualify as angle measures of a triangles, calculate their total sum and verify whether they add up to 180°
Set 1 - 41° + 112° + 52° = 205°
Set 2 - 25° + 130° + 25° = 180°
Set 3 - 30° + 40° + 90° = 160°
Set 4 - 132° + 141° + 31° = 304°
Therefore, only set 2 qualifies.
Answer:
3 Cubic x3−x2+5
Step-by-step explanation:
Step-by-step explanation:
hg=4
if correct then can we become friends
The distance travelled by an object is 50 m.
<h3>What is Distance?</h3>
The distance between two points is the length of the path connecting them.
Here, given equation of distance
S = 1/2 (u + v)t
Where s is the distance traveled by an object (in meters)
initial velocity u (in m/s)
final velocity v (in m/s).
t in seconds.
Now, given values are;
u = 8 m/s ; v = 12 m/s ; t = 5 sec.
S = 1/2 (8 + 12)5
S = 1/2 (20)5
S = 100/2
S = 50 m.
Thus, the distance travelled by an object is 50 m.
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