An equation is formed of two equal expressions. The cost of a new book is $7.43, while the cost of an old book is $8.86.
<h3>What is an equation?</h3>
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
Given the cost of 14 used books is $124. Therefore, the cost of a single used book is,
Cost of single used book(u) = 124/14 = $8.86
Also, the cost of 12 used books and 4 new books is $136. Therefore, the equation can be written as,
12u + 4n = 136
12(8.85) + 4n = 136
106.2 + 4n = 136
n = $7.43
Hence, the cost of a new book is $7.43, while the cost of an old book is $8.86.
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Answer:
Find all polar coordinates of point P where P = (5 , -pi+%2F6 ).
There are two sets of possibilities.
(1) Same (positive) magnitude and an angle that is the same as the given angle, or differs from the given angle by an even multiple of pi:
P = (5, -pi%2F6%2B2n%2Api )
(2) Opposite (negative) magnitude and an angle that differs from the given angle by an odd multiple of pi:
(-5, -pi%2F6%2B%282n%2B1%29pi)
answer is: (5,-pi%2F6+%2B+2n%2Api) or (-5, -pi%2F6%2B%282n%2B1%29pi)
Answer:
minimum value of function is
.
Step-by-step explanation:
Given function represents a parabola.
Now, here coefficient of
is positive , so the parabola will be facing upwards and thus the function will be having a minimum.
Now, as we know that minimum value of a parabolic function occurs at
x =
.
Where , b represents the coefficient of x and a represents the coefficient of
.
here, a = 2 , b = -6
Thus
=
=
So, at x =
minimum value will occur and which equals
y = 2×
-
+ 9 =
.
Thus , minimum value of function is
.
Answer:
This tells us that:
![A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%267%5C%5C5%26-8%5C%5C3%26-9%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
So we are saying we have scalars, c and d, such that:
.
So we want to find a way to express this as:
Ax=b where x is the scalar vector,
.
So we can write this as:
![\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%267%5C%5C5%26-8%5C%5C3%26-9%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dc%5C%5Cd%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-16%5C%5C3%5C%5C-15%5Cend%7Barray%7D%5Cright%5D)
Answer: 7208 remainder 5
Step-by-step explanation: