Answer:
∠2 , ∠3 , ∠5 ,∠6 are exterior angles
Step-by-step explanation:
Given : Figure.
To find : Which of the following are exterior angles.
Solution : We have given a figure with angle 1 ,2, 3,4,5,6.
Exterior angle : An angle which lies outside the closed figure.
We can see ∠1 and ∠4 area lies in closed figure.
But all other angle ∠2 , ∠3 , ∠5 ,∠6 are lies outside so, these are the exterior angles.
Therefore, ∠2 , ∠3 , ∠5 ,∠6 are exterior angles
Answer:
6.63
Step-by-step explanation:
So, the first 10 suits came with a commission of 5%, so for each suit it was:
250*5%
this is

but this counts for 10 suits, so together his commssion was 10*12.5=125 dollars
and the "extra" 3 suits came with a comittion of 5+3 percent, so 8 percent, which is

for each suit, and 60 in total.
his total comission was 125+60=185 dollars.
The cost of an order of 1 hamburger and 2 orders of fries cost which Nathaniel and Liam bought is $6.5.
<h3>What is system of equation?</h3>
A system of equation is the set of equation in which the finite set of equation is present for which the common solution is sought.
Let the cost of 1 hamburger is x dollar and 2 orders of fries is y dollars. Nathaniel bought 3 hamburgers and 2 orders of fries for $12.50. Thus,

Solve this equation as,
.....1
Liam bought 2 hamburgers and 4 orders of fries for $13. Thus,

Put the value of y in this equation and solve it further,

Put this value of x in equation 1,

The cost of an order of 1 hamburger and 2 orders of fries is,

Thus, the cost of an order of 1 hamburger and 2 orders of fries cost which Nathaniel and Liam bought is $6.5.
Learn more about the system of equations here;
brainly.com/question/13729904
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Answer:
0 ≤ an ≤ bn
The series ∑₁°° bn converges
The series ∑₁°° an converges by comparison to ∑₁°° bn.
0 ≤ an ≤ bn
The series ∑₁°° bn diverges
The comparison test is inconclusive for our choice of bn.
Step-by-step explanation:
an = 1 / (n² + n + 3) and bn = 1 / n²
The numerators are the same, and the denominator of an is greater than the denominator of bn. So 0 ≤ an ≤ bn.
bn is a p series with p > 1, so it converges.
Since the larger function converges, the smaller function also converges.
an = (3n − 1) / (6n² + 2n + 1) and bn = 1 / (2n)
If we rewrite bn as bn = (3n − 1) / (6n² − 2n), we can tell that when the numerators are equal, the denominator of an is greater than the denominator of bn. So 0 ≤ an ≤ bn.
bn is a p series with p = 1, so it diverges.
The larger function diverges. We cannot conclude whether the smaller function converges or diverges.