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Anettt [7]
3 years ago
9

Describe scalar and vector quantities. Include a definition and provide at least one example of how they are alike and how they

are different.
Physics
1 answer:
Lunna [17]3 years ago
8 0

Scalar quantities have only magnitude. example temperature, distance.

Vector quantities have magnitude and direction.Example force, velocity.

You can say "I applied a force p\of 3 newtons to the left" but you can't say I added 32 Fahrenheit to the left

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A basketball player throws the ball at a 47 angle above the horizontal to a hoop which is located a horizontal distance L = 5.0
FromTheMoon [43]

Answer:

v_0 =1.71

Explanation:

the parabolic movment is described by the following equation:

y = tan(a)x-\frac{1}{2v_0^2(cos(a))^2}gx^2

where y is the height of the ball, a is the angle of launch, v_0 the initial velocity, g the gravity and x is the horizontal distance of the ball.

So, if we want that the ball reach the hood, we will replace values on the equation as:

0.8 = tan(47)(5)-\frac{1}{2v_0^2(cos(47))^2}(9.8)(5)^2

Finally, solving for v_0, we get:

v_0=\sqrt{\frac{-9.8(5)^2}{(0.8-tan(47)(5))2cos^2(47)}}

v_0 =1.71

4 0
4 years ago
Which trait shared by dolphins and bats possibly lead to the evolution of echolocation in these two animal groups?
s344n2d4d5 [400]
The need to quickly move through dark environments.  <span />
6 0
3 years ago
Read 2 more answers
Which object(s) formed last in our solar system?
alexira [117]

Answer:

first option bro

Explanation:

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5 0
4 years ago
Jeremiah is riding his bicycle to the east. It takes him 10 seconds to change his velocity from 10 m/s to 15 m/s. What is Jeremi
Temka [501]

Answer:

5 m/s

Explanation:

he accelerates by 5 m/s so he accelerates from 10 m/s to 15 m/s so he accelerates 5 m/s

6 0
4 years ago
You throw a baseball directly upward at time t = 0 at an initial speed of 12.3 m/s. What is the maximum height the ball reaches
Semmy [17]

Explanation:

At the maximum height, the ball's velocity is 0.

v² = v₀² + 2a(x - x₀)

(0 m/s)² = (12.3 m/s)² + 2(-9.80 m/s²)(x - 0 m)

x = 7.72 m

The ball reaches a maximum height of 7.72 m.

The times where the ball passes through half that height is:

x = x₀ + v₀ t + ½ at²

(7.72 m / 2) = (0 m) + (12.3 m/s) t + ½ (-9.8 m/s²) t²

3.86 = 12.3 t - 4.9 t²

4.9 t² - 12.3 t + 3.86 = 0

Using quadratic formula:

t = [ -b ± √(b² - 4ac) ] / 2a

t = [ 12.3 ± √(12.3² - 4(4.9)(3.86)) ] / 9.8

t = 0.368, 2.14

The ball reaches half the maximum height after 0.368 seconds and after 2.14 seconds.

5 0
4 years ago
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