Question

In watching the examples of momentum by the student, he later used a 4.1 kg bowling ball to hit the pens about 3.5 seconds after he released the ball. By knowing that a bowling lane is 18.3 meters long you can calculate the momentum that the bowling ball hit the first pen with to be *

Answer 1

Answer:

Momentum = 21.44 N.s

Explanation:

First we need to find the speed of the ball by using following equation. Assuming the speed of ball to be constant:

$s = vt\\\\v = \frac{s}{t}$

where,

v = speed of ball = ?

s = distance covered by ball = 18.3 m

t = time taken = 3.5 s

Therefore,

$v = \frac{18.3\ m}{3.5\ s}\\\\v = 5.23\ m/s$

Now, the momentum of ball will be:

$Momentum = Mass*Velocity\\Momentum = (4.1\ kg)(5.23\ m/s)$

Momentum = 21.44 N.s