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Kaylis [27]
3 years ago
7

On a road trip, a driver achieved an average speed of (48.0+A) km/h for the first 86.0 km and an average speed of (43.0-B) km/h

for the remaining 54.0 km. What was her average speed (in km/h) for the entire trip? Round your final answer to three significant figures.
Physics
1 answer:
Bess [88]3 years ago
7 0

Answer:

45.94 km/h

Explanation:

Let the average speed be 48km/h for the first 86 km and 43 km/h for the remaining 54 km. We can calculate the time it takes to travel each of the segment:

For the first 86 km segment:

t_1 = s_1/v_1 = 86 / 48 = 1.79 hours

For the remaining 54 km segment:

t_2 = s_2/v_2 = 54 / 43 = 1.256 hours

So the total times it takes is

t = t_1 + t_2 = 1.79 + 1.256 = 3.047 hours

And the total distance she travels:

s = s_1 + s_2 = 86 + 54 = 140 km

The average speed for the entire trip would be total distance divided by total time:

v = s / t = 140 / 3.047 = 45.94 km/s

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1.42

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A 1180kg car is moving at a speed of 85.5 km/h. Find the force needed to bring the car to rest in a distance of 300m
yarga [219]

Answer:

1110 N

Explanation:

First, find the acceleration.

Given:

Δx = 300 m

v₀ = 85.5 km/h = 23.75 m/s

v = 0 m/s

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v² = v₀² + 2aΔx

(0 m/s)² = (23.75 m/s)² + 2a (300 m)

a = -0.94 m/s²

Find the force:

F = ma

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3 years ago
If a person weighs 1000 N on the surface of the Earth, how much will they weigh on the surface of the Moon? What “g” value shoul
Dafna1 [17]

Answer:

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Explanation:

from the question,

W = mg........................ Equation 1

Where W = weight of the man on Earth, m = mass of the man, g = acceleartion due to gravity of the man

make m the subject of the equation

m = W/g.............. Equation 2

Given: W = 1000 N,

Constant: g = 10 m/s²

Therefore,

m = 1000/10

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3 years ago
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Answer:

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So it is given as

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now we need to find the physical quantity which is defined as potential energy of a charge particle divided by its charge.

So it is given as

\frac{U}{q} = \int_\infty^r E.dr

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V = \frac{U}{q}

7 0
3 years ago
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