Answer:
1.42
Explanation:
<em> got it right on my homework </em>
Answer:
1110 N
Explanation:
First, find the acceleration.
Given:
Δx = 300 m
v₀ = 85.5 km/h = 23.75 m/s
v = 0 m/s
Find: a
v² = v₀² + 2aΔx
(0 m/s)² = (23.75 m/s)² + 2a (300 m)
a = -0.94 m/s²
Find the force:
F = ma
F = (1180 kg) (-0.94 m/s²)
F = -1110 N
The magnitude of the force is 1110 N.
Answer:
Hence the weight of the person on the moon is 162.4, and the value of g used is 1.624 m/s²
Explanation:
from the question,
W = mg........................ Equation 1
Where W = weight of the man on Earth, m = mass of the man, g = acceleartion due to gravity of the man
make m the subject of the equation
m = W/g.............. Equation 2
Given: W = 1000 N,
Constant: g = 10 m/s²
Therefore,
m = 1000/10
m = 100 kg
Weight on the moon
W' = mg'
W' = 100(1.624)
W' = 162.4 N.
Hence the weight of tthe person on the moon is 162.4, and the value of g used is 1.624 m/s²
Answer:
electric potential
Explanation:
Electric potential energy is defined by work done to move a charge very slowly from infinite to a given position.
So it is given as

now we need to find the physical quantity which is defined as potential energy of a charge particle divided by its charge.
So it is given as

so here energy to bring a unit test charge to move very slowly from infinite to a given position is define as electric potential of that given point
so relation is given as
