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alexgriva [62]
3 years ago
8

Solve the system using elimination.

Mathematics
1 answer:
Alchen [17]3 years ago
7 0
\left \{ {{7x+5y=15\ \ |*4} \atop {-6x-4y=-14\ \ |*5}} \right. \\\\ \left \{ {{28x+20y=60} \atop {-30x-20y=-70}} \right. \\+------\\
-2x=-10\ \ \ |Divide\ by\ -2\\
x=5\\\\
5y=15-7x\\
5y=15-7*5\\
5y=15-35\\
5y=-20\ \ \ |:5\\
y=-4\\\\\ Solution\ is\ B(5,-4).
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Find the area under the curve y = 13/x3 from x = 1 to x = t. Evaluate the area under the curve for t = 10, t = 100, and t = 1000
zvonat [6]

Answer:

t = 10

A = 32496.75

t = 100

A = 324999996.8

t = 1000

A=3.25\times 10^{12}

Step-by-step explanation:

The area under the curve is calculated by using the following definite integral:

A = \int\limits^t_ {1} \,{13\cdot x^{3}}  dx

A = 13 \int\limits^t_1 {x^{3}} \, dx

A = \frac{13}{4}\cdot (t^{4}-1)

Evaluated areas are presented below:

t = 10

A = 32496.75

t = 100

A = 324999996.8

t = 1000

A=3.25\times 10^{12}

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