Solve the system using elimination.

1 answer:

7 0

$\left \{ {{7x+5y=15\ \ |*4} \atop {-6x-4y=-14\ \ |*5}} \right. \\\\ \left \{ {{28x+20y=60} \atop {-30x-20y=-70}} \right. \\+------\\
-2x=-10\ \ \ |Divide\ by\ -2\\
x=5\\\\
5y=15-7x\\
5y=15-7*5\\
5y=15-35\\
5y=-20\ \ \ |:5\\
y=-4\\\\\ Solution\ is\ B(5,-4).$

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Mazyrski [523]

Answer:

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Step-by-step explanation:

To write the expression as a single logarithm, or condense it, use the properties of logarithms.

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So, in this case, we can move the 3 and the 4 inside the logarithms as exponents. Apply this property as seen below:

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2) The product property of logarithms states that $log_axy = log_ax+log_ay$ . In other words, the logarithm of a product is equal to the sum of the logarithms of its factors. So, in this case, write the expression as a single logarithm by taking the log (keep the same base) of the product of $w^3$ and $y^4$ . Apply the property as seen below and find the final answer.