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3 years ago

How do you turn 22% into a fraction in simplest form

2 answers:

7 0

Take 22 divided by 100. To get a decimal and then put that over 100 so the answer would be 22/100 I think I could be wrong

otez555 [7]3 years ago

4 0

Plz help me im in a hurry.....

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Find the diameter of a circle with an area of 95.03 square feet.

ra1l [238]

For this case we have that the area of a circle is given by:

$A = \pi * r ^ 2$

Where:

r: It is the radius of the circle

By clearing the radio we have:

$r = \pm \sqrt {\frac {A} {\pi}}$

We take the positive value:

$r = \sqrt {\frac {A} {\pi}}\\r = \sqrt {\frac {95.03} {\pi}}\\r = 5.50 \ ft$

The diameter is twice the radius:

$d = 11$

Answer:

$11 \ ft$

7 0

3 years ago

Read 2 more answers

How to know if the number is a perfect square

emmasim [6.3K]

Answer:

Step-by-step explanation:

Prime factorize the given number. All factors should have pair. If all factors have pair, then it is a perfect square

EG: 36 : Factors of 36 are 2,3,2,3. Here there are two 2's and two 3's. so 36 is a perfect square.

EG: 24: Factors of 12 are 2,2,3. Here 3 is without pair. so it is not a perfect square.

3 0

3 years ago

What is a-2÷5a+a+2÷5a

Andrej [43]

Answer:

=2a

Step-by-step explanation:

a-2/5a and a+2/5a cancel each other out and your left with a+a aka 2a

4 0

3 years ago

From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th

wel

Answer:

$\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}$

Step-by-step explanation:

The width of a square is its side length.

The width of a circle is its diameter.

Therefore, the largest possible circle that can be cut out from a square is a circle whose diameter is equal in length to the side length of the square.

Formulas

$\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}$

$\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

$\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}$

If the diameter is equal to the side length of the square, then:
$\implies \sf r=\dfrac{1}{2}s$

Therefore:

$\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}$