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Bas_tet [7]
3 years ago
10

A number cube with the numbers 1-6 is rolled 1000 times about how many times would it be expected that a number less than 5 is r

olled
Mathematics
2 answers:
mamaluj [8]3 years ago
7 0
666 times is what it should be
tresset_1 [31]3 years ago
6 0
That equal 5000 times he rolled
You might be interested in
1 1/8 +5/6 =<br><br> And then subtract 1/2 from the answer
kari74 [83]
Alright so start of with solving 1 1/8+5/6

Solve and you get 1 23/24

Now to subtract you have your answer subtracted by 1/2:

1 23/24-1/2=1 11/24

And so you get 1 11/24 

~Evie


8 0
3 years ago
Apples: $(2x) per pound
Ludmilka [50]

Answer:

Shopper spend $3 on Apples, $4 on Grapes and $3.5 on Oranges

Step-by-step explanation:

Cost of one pound of Apple = $2x

Cost of one pound of Grapes = $(6x-5)

Cost of one pound of Oranges = $(x+2)

A shopper purchases one pound each of  apples, grapes, and oranges and spends  $10.50.

It can be written as: 2x+6x-5+x+2=10.50

We need to find how much the shopper spend on each fruit.

First we need to find value of x by solving equation

2x+6x-5+x+2=10.50

Solving:

2x+6x+x+2-5=10.50\\9x-3=10.50\\9x=10.50+3\\9x=13.5\\x=\frac{13.5}{9}\\x=1.5

The value of x is: x=1.5

Now finding cost of one pound each fruit by putting x=1.5

Cost of one pound of Apple = $2x = 2(1.5) = $3

Cost of one pound of Grapes = $(6x-5) = (6(1.5)-5)= $4

Cost of one pound of Oranges = $(x+2)=(1.5+2)=$3.5

So,

Cost of one pound of Apple  = $3

Cost of one pound of Grapes = $4

Cost of one pound of Oranges = $3.5

So, shopper spend $3 on apples, $4 on Grapes and $3.5 on Oranges

3 0
3 years ago
Match each number with its place in order from smallest (1st) to largest (6th).
zheka24 [161]
90 would be the largest then 59,48, -56, -80, and leaving -84 to be the smallest
8 0
3 years ago
LaShea would like to invest her $100 in birthday money. Which option will give her the most money at the end of the investment p
Gnom [1K]
Third choice because 1,5 years at 7 percent would of been kore
3 0
3 years ago
Read 2 more answers
If \: x + y + z = 0 \: then \: show \: that \: {x}^{3} + {y}^{3 } + {z}^{3} =3xy<br>​
tankabanditka [31]

Answer:

Given

x+y+z=0

⟹x+y=−z

Cubing on both sides

(x+y) 3 =(−z) 3

⟹x 3 +y 3 +3x 2y+3xy 2 =−z 3

⟹x 3 +y 3 +3xy(x+y)=−z 3

⟹x 3+y 3+3xy(−z)=−z 3

⟹x 3 +y 3−3xyz=−z 3

⟹x 3 +y 3 +z 3 =3xyz

Step-by-step explanation:

Hope it is helpful.....

8 0
3 years ago
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