g(x) = the quantity of x minus one, over four
g(x) = (x-1)/4
g(5) = (5-1)/4
g(5) = 4/4
g(5) = 1
f(x) = x2 − 3x + 3
f(g(5)) =1^2 − 3(1) + 3
f(g(5)) = 1 - 3 + 3
f(g(5)) = 1
Answer:
correct do
Step-by-step explanation:
Answer:
![\left[\begin{array}{ccc}1&\frac{3}{4}\\2&\frac{9}{16}\\3&\frac{27}{48}\\4&\frac{81}{144}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26%5Cfrac%7B3%7D%7B4%7D%5C%5C2%26%5Cfrac%7B9%7D%7B16%7D%5C%5C3%26%5Cfrac%7B27%7D%7B48%7D%5C%5C4%26%5Cfrac%7B81%7D%7B144%7D%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
It is basically substituting the numbers in the function.
For 1, it will be
Same for the rest.
Answer:
Step-by-step explanation:
its no way to answer how u texted it
Answer:
The answer is D
Step-by-step explanation:
Each blue dot over the number represents that number one time. There is one bot over 145 so there is only one 145. There are 5 dots over 165, so you write 165 five times and so on.
