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4 years ago

The cube has a mass of 72.9 g. What substance is this cube composed of?

Physics

1 answer:

aalyn [17]4 years ago

8 0

I Need More Details.
But here is somthing i found maybe the same.
brainly.com/question/1354966

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Changes in the forms of energy are called

Dima020 [189]

<span>Changes in the forms of energy are called "Energy Conversions"

Hope this helps!</span>

5 0

3 years ago

Who’s going faster in the attached image?

ioda

Answer:

Art

Explanation:

Polly's line is linear, while arts line is going up with constant velocity. There for art is going faster.

8 0

3 years ago

Read 2 more answers

A drowsy cat spots a flower pot that sails first up and then down past an open window. The pot was in view for a total of 0.56 s

liberstina [14]

Answer:

$h = 0.028 m$

Explanation:

As we know that

$d = \frac{v_2 + v_1}{2} t$

here we have

$1.95 = \frac{v_2 + v_1}{2}(0.56)$

$v_2 + v_1 = 6.96$

also we know

$v_2 - v_1 = at$

$v_2 - v_1 = (9.81)(0.56)$

$v_2 - v_1 = 5.49$

so we have

$v_2 = 6.23 m/s$

$v_1 = 0.74 m/s$

so the height above window is given as

$v_f^2 - v_i^2 = 2 a d$

$0.74^2 - 0 = 2(9.81)h$

$h = 0.028 m$

4 0

4 years ago

1. Two astronauts are 2.00 m apart in their spaceship. One speaks to the other. The conversation is transmitted to earth via ele

Veronika [31]

Answer:

$1.6949*10^6 m$

Explanation:

Our values are

$d=2m$

$v=354m/s$

We can find the time through

$t=\frac{d}{v}$

$t=\frac{2}{354}$

$t=5.64*10^{-3}s$

The expression for the distance between the Earth and the spaceship is as follow:

$d=ct$

Where c is Light speed, and t our previous time.

$d= (3*10^8)(5.64*10^{-3})$

$d= 1.6949*10^6m$

Therefore the distance between the Eath and the Spaceship is $1.6949*10^6$ m

4 0

4 years ago

A 10 kg dog runs across the ground and jumps onto an ice-covered pond at 5 m/s. If the force of friction acting on the dog is 8

zzz [600]

Answer:

15.625m

Explanation:

Using the equation of motion

v² = u²+2as

u and v are the initial and final velocities

a is the acceleration

s is the distance

Get the acceleration

According to Newton's second law;

F = ma

8 = 10a

a = 8/10

a = 0.8m/s²

We are also given

v = 5m/s

u = 0m/s

Substitute into the formula above

v² = u²+2as

5² = 0²+2(0.8)s

25 = 1.6s

s = 25/1.6

s = 15.625m

Hence the dog will cover a distance of 15.625m before coming to rest

3 0

3 years ago