a) 32 kg m/s
Assuming the spring is initially at rest, the total momentum of the system before the collision is given only by the momentum of the bowling ball:

The ball bounces off at the same speed had before, but the new velocity has a negative sign (since the direction is opposite to the initial direction). So, the new momentum of the ball is:

The final momentum after the collision is the sum of the momenta of the ball and off the spring:

where
is the momentum of the spring. For the conservation of momentum,

b) -32 kg m/s
The change in momentum of bowling ball is given by the difference between its final momentum and initial momentum:

c) 64 N
The change in momentum is equal to the product between the average force and the time of the interaction:

Since we know
, we can find the magnitude of the force:

The negative sign simply means that the direction of the force is opposite to the initial direction of the ball.
d) The force calculated in the previous step (64 N) is larger than the force of 32 N.
Explanation:
R = V/I
Since this is an I/V graph, the greater the slope of the line the lower the R value.
Hence we find the line with the smallest slope, which is conductor M.
B.) <span>The range of all electromagnetic radiation is known as the "Electromagnetic Spectrum"
Hope this helps!
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Answer:

Explanation:
The equivalent of Newton's second law for rotational motions is:

where
is the net torque applied to the object
I is the moment of inertia
is the angular acceleration
In this problem we have:
(net torque, with a negative sign since it is a friction torque, so it acts in the opposite direction as the motion)
is the moment of inertia
Solving for
, we find the angular acceleration:
