Two identical 0.50-kg carts, each 0.10 m long, are at rest on a low-friction track and are connected by a spring that is initial
1 answer:
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Answer:
-0.04194 V
Explanation:
= Number of turns in outer solenoid = 330
= Number of turns in inner solenoid = 22
= Current in inner solenoid = 0.14 A
= Rate of change of current = 1800 A/s
= Vacuum permeability =
r = Radius = 0.0115 m
Magnetic field is given by
The average magnetic flux through each turn of the inner solenoid is
Magnetic flux is given by
Mutual inductance is given by
The mutual inductance of the two solenoids is
Induced emf is given by
The emf induced in the outer solenoid by the changing current inthe inner solenoid is -0.04194 V