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Nataliya [291]
3 years ago
5

Who’s going faster in the attached image?

Physics
2 answers:
ioda3 years ago
8 0

Answer:

Art

Explanation:

Polly's line is linear, while arts line is going up with constant velocity. There for art is going faster.

Juliette [100K]3 years ago
6 0

There isn't a simple answer to that question.

Polly is going at a steady speed for the whole 5 seconds.  She must have started before time-zero, because AT time-zero, she's already moving at 1m/s, and she stays at that steady speed for at least the next 5 seconds that we know of.  (That's all the graph tells us.)

Art is standing at the starting line, waiting for the signal to GO.  At time zero, he's not moving at all, so Polly is moving faster than he is.  

At time-zero, (when the starter fires the pistol ?), Art <u>starts</u> moving AND building up speed.  He builds up speed steadily, going faster and faster.  His speed builds and builds all the way across the graph.  He starts out with zero speed, and he <em>accelerates</em> so that his speed grows by 1 m/s every 2 sec.  After 2 sec, he's moving at 1 m/s, and after 4 sec, he's built it up to 2 m/s.

Polly is moving at 1 m/s all across the graph, for the whole 5 sec. So she's going faster than Art is, <em>for the first 2 seconds</em>.  But Art is building his speed, faster and faster.  He reaches 1 m/s after 2 sec, and <u>after that</u> he's going faster that Polly.  

All this information that I'm saying is on the graph.  I'm just describing the graph in painful boring detail.  As you read my description, you should be able to look over at the graph every time I say something, and see it there.

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Explanation:

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5 0
3 years ago
A satellite with mass 6000 kg is orbiting the planet at 2500 km above the planet's
9966 [12]

By the law of universal gravitation, the gravitational force <em>F</em> between the satellite (mass <em>m</em>) and planet (mass <em>M</em>) is

<em>F</em> = <em>G</em> <em>M</em> <em>m</em> / <em>R </em>²

where

<em>• G</em> = 6.67 × 10⁻¹¹ m³/(kg•s²) is the universal gravitation constant

• <em>R</em> = 2500 km + 5000 km = 7500 km is the distance between the satellite and the center of the planet

Solve for <em>M</em> :

<em>M</em> = <em>F R</em> ² / (<em>G</em> <em>m</em>)

<em>M</em> = ((3 × 10⁴ N) (75 × 10⁵ m)²) / (<em>G</em> (6 × 10³ kg))

<em>M</em> ≈ 2.8 × 10¹⁴ kg

6 0
2 years ago
Tech A says that a relay is a one-way electrical check valve used in alternators to change AC into DC. Tech B says that a relay
Setler [38]

Answer:

The correct answer is from Tech B.

Explanation:

The relay is an electromagnetic device, which is stimulated by a very weak electrical current to open or close a circuit.  It functions as a switch controlled by an electrical circuit in which, by means of a coil and an electromagnet, a sequence of one or several contactors is activated that allow to open or close other electrical circuits independent of the one that controls it.

Have a nice day!

7 0
3 years ago
How much work is done when a 100 N force moves a block 59 m?
xxTIMURxx [149]

Answer:

5900J

Explanation:

Work=Forse*Distance

work = J, Jewls

100*59=5900

Hop this helps and can u think about brainlist

i put a picture on how to find these answers, if u got any more questions im here

3 0
3 years ago
A space shuttle sits on the launch pad for 2.0 minutes, and then goes from rest to 4600 m/s in 8.0 minutes. Treat its motion as
SpyIntel [72]

Answer:

a.) a = 0 ms⁻²

b.) a = 9.58 ms⁻²

c.) a = 7.67 ms⁻²

Explanation:

a.)

    Acceleration (a) is defined as the time rate of change of velocity

                       a = \frac{v_{2} - v_{1} } {t}  

Given data

 Final velocity = v₂ = 0 m/s

 Initial velocity = v ₁ = 0 m/s

  As the space shuttle remain at rest for the first 2 minutes i.e there is no change in velocity so,

                 a = 0 ms⁻²

b.)

     Given data

As the space shuttle start from rest, So initial velocity is zero

    Initial velocity = v₁ = 0 ms⁻¹

    Final velocity  = v₂ = 4600 ms⁻¹

     Time = t = 8 min = 480 s

By the definition of Acceleration (a)

             a = \frac{v_{2} - v_{1} } {t}  

             a = \frac{4600 - 0 } {480}

                     a = 9.58 ms⁻²

c.)

    Given data

As the space shuttle is at rest for first 2 min then start moving, So initial velocity is zero

    Initial velocity = v₁ = 0 ms⁻¹

    Final velocity  = v₂ = 4600 ms⁻¹

     Time = t = 10 min = 600 s

By the definition of Acceleration (a)

             a = \frac{v_{2} - v_{1} } {t}  

             a = \frac{4600 - 0 } {600}

                     a = 7.67 ms⁻²

8 0
3 years ago
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