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Nataliya [291]
3 years ago
5

Who’s going faster in the attached image?

Physics
2 answers:
ioda3 years ago
8 0

Answer:

Art

Explanation:

Polly's line is linear, while arts line is going up with constant velocity. There for art is going faster.

Juliette [100K]3 years ago
6 0

There isn't a simple answer to that question.

Polly is going at a steady speed for the whole 5 seconds.  She must have started before time-zero, because AT time-zero, she's already moving at 1m/s, and she stays at that steady speed for at least the next 5 seconds that we know of.  (That's all the graph tells us.)

Art is standing at the starting line, waiting for the signal to GO.  At time zero, he's not moving at all, so Polly is moving faster than he is.  

At time-zero, (when the starter fires the pistol ?), Art <u>starts</u> moving AND building up speed.  He builds up speed steadily, going faster and faster.  His speed builds and builds all the way across the graph.  He starts out with zero speed, and he <em>accelerates</em> so that his speed grows by 1 m/s every 2 sec.  After 2 sec, he's moving at 1 m/s, and after 4 sec, he's built it up to 2 m/s.

Polly is moving at 1 m/s all across the graph, for the whole 5 sec. So she's going faster than Art is, <em>for the first 2 seconds</em>.  But Art is building his speed, faster and faster.  He reaches 1 m/s after 2 sec, and <u>after that</u> he's going faster that Polly.  

All this information that I'm saying is on the graph.  I'm just describing the graph in painful boring detail.  As you read my description, you should be able to look over at the graph every time I say something, and see it there.

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a projectile whose masss is 10g is fired directly upward from ground level with an initial velocity of 1000m/s neglecting the ef
sammy [17]

Answer:

<em>The speed of the projectile when it impacts the ground is 1000 m/s</em>

Explanation:

<u>Vertical Launch</u>

When an object is launched vertically and upwards it starts to move at an initial speed vo, then the acceleration of gravity makes that speed to reduce until it reaches 0. The object has reached its maximum height. Then, it starts to move downwards in free fall, with initial speed zero and gradually increasing it until it reaches the ground level. We will demonstrate that the speed it has when impacts the ground is the same (and opposite) as the initial speed vo.

The speed when the object is moving upwards is given by

v_f=v_o-g.t

The time it takes to reach the maximum height is when vf=0, i.e.

0=v_o-g.t

solving for t

\displaystyle t=\frac{v_o}{g}

The maximum height reached is

\displaystyle y=\frac{gt^2}{2}=\frac{v_o^2}{2g}

Then, the object starts to fall. The object's height is given by

\displaystyle y=\frac{v_o^2}{2g}-\frac{gt'^2}{2}

where t' is the time the object has traveled downwards. The height will be 0 again when

\displaystyle \frac{v_o^2}{2g}=\frac{gt'^2}{2}

Solving for t'

\displaystyle t'=\frac{v_o}{g}

We can see the time it takes to reach the maximum height is the same it takes to return to ground level. Of course, the speed when it happens is

v_f=g.t'=v_o

Thus, the speed of the projectile when it impacts the ground is 1000 m/s

4 0
4 years ago
Write any two importance of gravitational force​
saul85 [17]

Answer:

plz mark me as brainliest plz

Explanation:

The gravitational force of the earth keeps us bound to the earth. Gravitational force between earth and sun makes the earth move around the sun. Gravitational force between moon and earth makes the moon go around the earth.

5 0
3 years ago
calculate the force exerted on a rocket given that the propelling gases are expelled at a rate of 1500 kg/s with a speed of 4.0x
Tanya [424]

we know that momentum is given as

P = mv

where P = momentum , m = mass , v = velocity

taking derivative both side relative to "t"

dP/dt = v (dm/dt)

we know that :  dP/dt  = F = force

hence

F = v (dm/dt)

given that :

dm/dt = rate of mass expelled = 1500 kg/s

v = velocity = 4 x 10⁴ m/s

hence  , inserting the values in the above formula

F = (4 x 10⁴) (1500)

F = 6 x 10⁷ N



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1600 N
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Describe the process of sexual reproduction in terms of the life cycle of cells.
umka2103 [35]
The first growth phase (G1): During the G1 stage, the cell doubles in size and doubles the number of organelles.

The synthesis phase (S): The DNA is replicated during this phase. In other words, an identical copy of all the cell’s DNA is made. This ensures that each new cell has a set of genetic material identical to that of the parental cell. This process is called DNA replication.

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