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avanturin [10]
2 years ago
14

Find two number whose sum is 60 such that the sum of the square of one number plus 12 times the other number is a minimum

Mathematics
1 answer:
Alex17521 [72]2 years ago
7 0
60=x^2+12
x^2=48
x=6.93

Hope this helps
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Subtract -2x^2+4x-1−2x
vivado [14]

Answer:

8x²- x -8

Step-by-step explanation:

The question is not well written. I guess what you mean is:

Subtract -2x^2+4x-1 ( minus 2x squared plus 4x minus 1) from 6x^2+3x-9 (6x squared plus 3x minus 9).

To  subtract -2x^2+4x-1 from 6x^2+3x-9, that is

6x^2+3x-9 - (-2x^2+4x-1). This can be written as

6x²+3x-9 - (-2x²+4x-1)

Now, opening the bracket, we will get

6x²+3x-9 +2x²-4x+1

Then, collecting like terms, we get

6x²+2x²+3x-4x-9+1

6x²+2x² = 8x²

3x-4x = -x

-9+1 = -8

∴6x²+2x²+3x-4x-9+1 becomes

8x²-x -8

The answer is 8x²-x -8.

7 0
3 years ago
If f(x) = 5x - 1 and g(x) = 2x^2 + 1 , what is the value of ( f x g )(-3) ?
Genrish500 [490]
The answer is b hope this helps
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2 years ago
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How do u write 19/25 fraction or mixed number as a decimal
Romashka [77]
Divide the bottom into the top for a decimal
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Plz help due tommorow big grade
Korvikt [17]
It would take 4750 because 1L is 5000 ml and 5000-250=4750. Use the web to do it in metric measurements.
3 0
2 years ago
HELP PLEASE I KEEP ASKING AND NO ONE ACTUALLY HELPS
coldgirl [10]

Answer: X = 44.4 degrees

Step-by-step explanation: The figure given is a right angled triangle with two sides given as well as one angle unknown.

Angle X, which is the unknown, is the reference angle in this question. So we have an opposite which is the side facing the reference angle (line 7 units) and we have an hypotenuse which is the side facing the right angle (line 10). Having an opposite and an hypotenuse, we can use the trigonometric ratio of sine.

SinX = opposite/hypotenuse

SinX = 7/10

SinX = 0.7000

Looking up a table of values or checking the calculator, 0.7000 under sine of angles gives 44.4270

Therefore angle X is approximately 44.4 degrees (approximated to the nearest tenth)

3 0
3 years ago
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