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olya-2409 [2.1K]
3 years ago
8

What is the discount on a leather jacket that costs $298 discounted at 15%

Mathematics
2 answers:
levacccp [35]3 years ago
7 0
<span>The correct answer is 253.3 US$</span>
snow_lady [41]3 years ago
6 0
You take 298 x .15 =44.7
298-44.7=253.3
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One reading an Antarctic research station showed that the temperature was -35 degrees Celsius what is this temperature in degree
Musya8 [376]
It is very simple it would be positive but would remain 35
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3 years ago
Which equation could be used to solve problems involving the relationships between the angles?
Salsk061 [2.6K]

Answer:

B

Step-by-step explanation:

The answer is B I just had this question

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3 years ago
The sanchez family goes out for dinner, and the price of the meals is $60. The sales tax on the Meals is 7 percent, and they als
dem82 [27]

Answer:

73.3

Step-by-step explanation:

7%=7÷100=0.07 ×60=4.2

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5 0
3 years ago
Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt
polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt

=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k

The first integral is trivial since (\tan t)'=\sec^2t.

The second can be done by substituting u=t^2-1:

u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C

The third can be found by integrating by parts:

u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t

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\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C

8 0
3 years ago
For what value of x is the rational expression below equal to zero?<br> 2-X<br> 2 + x
s344n2d4d5 [400]

Answer:

2

Step-by-step explanation:

If you divide 0 by any number you will get 0

If you will substitute x for 2 you will have:

2-2/2+2=0/4=0

3 0
3 years ago
Read 2 more answers
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