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2 years ago

8

If f(x)=4x-5 and g(x)=3-2x find f(x)+g(x)

1 answer:

Akimi4 [234]2 years ago

8 0

(fg)(x) = [f(x)][g(x)]
(fg)(x) = (4x - 5)(3) = 12x - 15

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Step-by-step explanation

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2 years ago

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\large -\frac{2}{3}x+3=\frac{2}{3}x+\frac{1}{3}

german

Answer:

$\boxed {x = 2}$

Step-by-step explanation:

Solve for the value of $x$ :

$-\frac{2}{3}x + 3 = \frac{2}{3}x + \frac{1}{3}$

-Take $\frac{2}{3}x$ and subtract it from $-\frac{2}{3}x$ :

$-\frac{2}{3}x + 3 -\frac{2}{3}x = \frac{2}{3}x - \frac{2}{3}x + \frac{1}{3}$

$-\frac{4}{3}x + 3 = \frac{1}{3}$

-Subtract both sides and convert $3$ to a fraction:

$-\frac{4}{3}x + 3 - 3 = \frac{1}{3} - 3$

$-\frac{4}{3}x = \frac{1}{3} - \frac{9}{3}$

Since both $\frac{1}{3}$ and $\frac{9}{3}$ have the same denominator, then you would subtract the numerator:

$-\frac{4}{3}x = \frac{1 - 9}{3}$

$-\frac{4}{3}x = \frac{8}{3}$

-Multiply both sides by $-\frac{3}{4}$ , which is the reciprocal of $-\frac{4}{3}$ :

$x = \frac{8}{3} (-\frac{3}{4})$

$x = \frac{-8(-3)}{3 \times 4}$

$x = \frac{24}{12}$

-Divide $24$ by $12$ :

$x = \frac{24}{12}$

$\boxed {x = 2}$

So, therefore, the value of $x$ is $2$ .

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3 years ago

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Andre45 [30]

Answer:

15.81

Step-by-step explanation:

Please mark brainliest if this has helped. Have a good day and goodluck with your work!

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