Answer:
Volume of a cup
The shape of the cup is a cylinder. The volume of a cylinder is:
\text{Volume of a cylinder}=\pi \times (radius)^2\times heightVolume of a cylinder=π×(radius)
2
×height
The diameter fo the cup is half the diameter: 2in/2 = 1in.
Substitute radius = 1 in, and height = 4 in in the formula for the volume of a cylinder:
\text{Volume of the cup}=\pi \times (1in)^2\times 4in\approx 12.57in^3Volume of the cup=π×(1in)
2
×4in≈12.57in
3
2. Volume of the sink:
The volume of the sink is 1072in³ (note the units is in³ and not in).
3. Divide the volume of the sink by the volume of the cup.
This gives the number of cups that contain a volume equal to the volume of the sink:
\dfrac{1072in^3}{12.57in^3}=85.3cups\approx 85cups
12.57in
3
Step-by-step explanation:
Answer:
The right answer to your question is the third option
Step-by-step explanation:
5 √12xm³
First find the prime factors of 12
12 2
6 2
3 3
1 Then 12 = 2² 3
and m³ = m m²
So 5 √ 2² 3 x m m²
and 5 (2)(m) √ 3xm
10 m √ 3xm
We know the area of the middle rectangle is 48 (length * width). removing that rectangle leaves us with two semicircles. you can combine those semicircles to be the equivalent of one circle. the area for a circle is r^2 * pi. we know the diameter is 4 because that is where we cut the semicircles. radius is half the diameter, so r is 2. 2^2 is 4, 4* pi is 12.56. add 12.56 (area of semicircles) with 48 (area of rectangle) and we get 60.56
Answer:
tanA = sinA / cosA = 3/5 / 4/5 = 3/4.
