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Amiraneli [1.4K]

3 years ago

7

A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At

what rate is x changing when x = 1?
Decreasing one fifth unit/sec

Increasing one fifth unit/sec

Decreasing one tenth unit/sec

Increasing one tenth unit/sec

1 answer:

Shtirlitz [24]3 years ago

8 0

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

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Homogenized milk has a density of 1.032 kg/L and heavy cream has a density of 1.005 kg/L at 10°C. At 10°C, a container holding 8

Bumek [7]

Answer:

It's heavy cream

Step-by-step explanation:

Homogenized milk has a density of 1.032 kg/L and

heavy cream has a density of 1.005 kg/L at 10°C.

At 10°C, a container holding 8 liters of liquid weighs 8.04 kilograms

To determine which container hold homogenized milk or heavy cream and How I know?

We findo the density of the measurements given and whatever it correspond to is what it is

First mass is 8.04kg

Liquid contained is 8 litres

SInce the density is kg/L

No need for conversion

Density = mass/volume = 8.04/8= 1.005kg/L

Heavy cream has a density of 1.005 kg/L at 10°C.

Therefore it correspond

5 0

3 years ago

What is the rate of change for this imagine

GaryK [48]

3, -1

Step-by-step explanation:

It goes 3 to the positive side

and one down side

4 0

3 years ago

Read 2 more answers

A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the

leva [86]

The length of the bridge is the distance from the beginning to the end.

<em>The distance b between each beam is 9ft.</em>

Let:

<em /> $I \to$ <em> I-Beam</em>

<em /> $d_I \to$ <em> distance between I beam and the bridge</em>

<em /> $b \to$ <em> distance between each I beam</em>

<em />

Given that:

$I = \frac 34 ft\\$

$d_I = 3 ft$

<em /> $Length = 55ft\ 6in$ <em> --- length of the bridge</em>

<em />

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

$L_1 = 6 \times I$

$L_1 = 6 \times \frac 34$

$L_1 = \frac {18}4$

$L_1 = 4.5ft$

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

$d_1 =2 \times d_I$

$d_1 =2 \times 3ft$

$d_1 =6ft$

There are 5 spaces between the I-beams

So, the length of the total spaces is:

$L_2 = 5 \times b$

$L_2 = 5b$

The total length is:

$Length = L_1 + d_1 + L_2$

So, we have:

$4.5ft + 6ft + 5b = 55ft\ 6in$

Collect like terms

$5b = 55ft\ 6in - 4.5ft - 6ft$

$5b = 44.5ft\ 6in$

Convert inches to feet

$5b = 44.5ft\ + \frac{6}{12}ft$

$5b = 44.5ft\ + 0.5ft$

$5b = 45ft$

Divide both sides by 5

$b = 9ft$

<em>Hence, the distance (b) between each beam is 9ft.</em>

Read more about lengths at:

brainly.com/question/22059747

3 0

2 years ago

What is scarerude of 90

lora16 [44]

Assuming you meant square root of 90 it would be

90 equals 3 times the square root of 10
√90 = 3√10

4 0

2 years ago

Problem #1: Mrs. Grape has 90 students. On her last test, 3/10 of these students earned an A. Of those students, 1/9 got a perfe

fredd [130]

Answer:

3 students got a perfect score.

Step-by-step explanation:

Total number of students in Mrs. Grape's class = 90

Number of students who earned an A = 3/10 of 90

= $\frac{3}{10}\times 90$

= 27 students

Out of 27 students the number of students who got perfect score

= $\frac{1}{9}\times 27$

= 3 students

3 students got a perfect score.

7 0

2 years ago