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3 years ago

Please put a serious answer

Mathematics

1 answer:

aksik [14]3 years ago

8 0

Answer:

x=12

Step-by-step explanation:

9x-14=2(3x+11)

9x-14=6x+22

9x-6x=22+14

3x=36

x=36/3=12

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3 years ago

WORTH 20 POINTS HELP

vfiekz [6]

Below represents the proof that the quadrilateral QRST is a parallelogram

<h3>How to prove that QRST is a parallelogram?</h3>

The coordinates are given as:

Q = (-1,-1)

R = (2,9)

S = (-4,5)

T = (-7,-5)

Calculate the length of each side using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$QR = \sqrt{(-1 - 2)^2 + (-1 -9)^2} = \sqrt{109}$

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$ST = \sqrt{(-7 + 4)^2 + (-5 - 5)^2} = \sqrt{109}$

$TQ = \sqrt{(-7 + 1)^2 + (-5 + 1)^2} = \sqrt{52}$

The above computations show that opposite sides are equal.

Next, we determine the slope of each side using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$QR = \frac{9 + 1}{2 + 3} = \frac{10}3$

$RS = \frac{5-9}{-4 - 2} = \frac{2}3$

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Read more about parallelograms at:

brainly.com/question/3050890

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2 years ago

Wich of the following equations would NOT contain the point (4,12)

nlexa [21]

Given:

The given point is (4,12).

To find:

The equation that would NOT contain the point (4,12).

Solution:

We need to check each equation for the point (4,12).

In option A, the given equation is:

$y=-2x+20$

Putting $x=4$ , we get

$y=-2(4)+20$

$y=-8+20$

$y=12$

This equation contains the point (4,12).

In option B, the given equation is:

$y=\dfrac{1}{2}x+8$

Putting $x=4$ , we get

$y=\dfrac{1}{2}(4)+8$

$y=2+8$

$y=10$

This equation does not contain the point (4,12).

In option C, the given equation is:

$y=-\dfrac{1}{2}x+14$

Putting $x=4$ , we get

$y=-\dfrac{1}{2}(4)+14$

$y=-2+14$

$y=12$

This equation contains the point (4,12).

In option D, the given equation is:

$y=\dfrac{3}{4}x+9$

Putting $x=4$ , we get

$y=\dfrac{3}{4}(4)+9$

$y=3+9$

$y=12$

This equation contains the point (4,12).

Only the equation in option B does NOT contain the point (4,12). Therefore, the correct option is B.

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