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2 years ago

5

. This is a problem from Kendra's homework and the sum she found. Though she thought she followed the correct steps to find the

sum, she knows her answer could not be correct. What could be a reason she believes she is incorrect?

1 answer:

nlexa [21]2 years ago

6 0

She didn't estimate her answer first

WHAT IS THE QUESTION ON KENDRA'S HOMEWORK?

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Suppose you just received a shipment of twelve televisions. Three of the televisions are defective. If two televisions are rando

qwelly [4]

Answer: The probability that both televisions work is 0.5625 .

The probability at least one of the two televisions does not work is 0.4375.

Step-by-step explanation:

Given : Number of televisions received in shipment= 12

Number of defective televisions received in shipment= 3

Then proportion of defective televisions = $\dfrac{3}{12}=0.25$

Using binomial probability formula, the probability of getting success in x trials is given by :-

$P(x)=^nC_xp^x(1-p)^{n-x}$

If two televisions are randomly selected, then the probability that both televisions work will be :-

$P(0)=^2C_0(0.25)^0(0.75)^2=(0.75)^2=0.5625$

The probability at least one of the two televisions does not work will be :-

$P(x\geq1)=1-P(0)=1-0.5625=0.4375$

6 0

2 years ago

Can anyone help me with this math problem? Thank you.

pickupchik [31]

Step-by-step explanation:

Answer is in the picture.

4 0

3 years ago

What is the solution to the inequality 10x + 18 < -2

solong [7]

<h3>Answer: x < -2, choice B</h3>

===========================================

Work Shown:

10x + 18 < -2

10x + 18-18 < -2-18 ... subtract 18 from both sides

10x < -20

10x/10 < -20/10 ... divide both sides by 10

x < -2

3 0

3 years ago

Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form? 5x + 3y = 18 5x – 3y = 30

ddd [48]

$\bf C(\stackrel{x_1}{3}~,~\stackrel{y_1}{-5})\qquad 
D(\stackrel{x_2}{6}~,~\stackrel{y_2}{0})
\\\\\\
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-(-5)}{6-3}\implies \cfrac{0+5}{6-3}\implies \cfrac{5}{3}
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=\cfrac{5}{3}(x-3)\implies y+5=\cfrac{5}{3}(x-3)$

$\bf \stackrel{\textit{multiplying both sides by LCD of 3}}{3(y+5)=3\left[ \cfrac{5}{3}(x-3) \right]}\implies 3y+15=5(x-3)
\\\\\\
3y+15=5x-15\implies -5x+3y=-30\implies \stackrel{\textit{multiplying by -1}}{5x-3y=30}$

bearing in mind the standard form uses all integers, and the x-variable cannot have a negative coefficient.

6 0

3 years ago

Read 2 more answers

Help me please I need to finish

IrinaK [193]

The awnser is c give me brainliest

8 0

2 years ago

Read 2 more answers