Cost per metre = Rs. 5
Total cost = Rs. 2000
Then total length of the fence = Rs.2000/Rs.5
= 400 metre
Total length of the fence = 400 metre
Given:
The function is
To find:
The zeros of the given function.
Solution:
The general form of polynomial is
...(i)
where, a is a constant, are zeros of respective multiplicities .
We have,
On comparing this with (i), we get
It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.
Therefore, the correct option is B.
Answer:
The graph of the circle is not a function
Answer:
Here we will simplify 2/50 to its simplest form and convert it to a mixed number if necessary.
In the fraction 2/50, 2 is the numerator and 50 is the denominator.
When you ask "What is 2/50 simplified?", we assume you want to know how to simplify the numerator and denominator to their smallest values, while still keeping the same value of the fraction.
We do this by first finding the greatest common factor of 2 and 50, which is 2.
Then, we divide both 2 and 50 by the greatest common factor to get the following simplified fraction:
1/25
Therefore, this equation is true:
2/50 = 1/25
If the numerator is greater than or equal to the denominator of a fraction, then it is called an improper fraction. In that case, you could convert it into a whole number or mixed number fraction.
1/25 = Proper Fraction
Step-by-step explanation:
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Answer:
Ф = 0 and Ф = π
Step-by-step explanation:
* Lets explain how to solve the problem
∵ sin Ф + 1 = cos²Ф, where 0 ≤ Ф < 2π
- To solve we must to replace cos²Ф by 1 - sin²Ф
∵ sin²Ф + cos²Ф = 1
- By subtracting sin²Ф from both sides
∴ cos²Ф = 1 - sin²Ф
- Lets replace cos²Ф in the equation above
∴ sin Ф + 1 = 1 - sin²Ф
- Subtract 1 from both sides
∴ sin Ф = - sin²Ф
- Add sin²Ф for both sides
∴ sin²Ф + sin Ф = 0
- Take sin Ф as a common factor from both sides
∴ sin Ф(sin Ф + 1) = 0
- Equate each factor by 0
∵ sin Ф = 0
∴ Ф = 0 OR Ф = 2π
∵ sin Ф + 1 = 0
- Subtract 1 from both sides
∴ sin Ф = -1
∴ Ф = π
∵ 0 ≤ Ф < 2π
∵ Ф < 2π
∴ We will refused the answer Ф = 2π
∴ Ф = 0 and Ф = π